Consider the function g(x) = –2x+3 x + 1 17. 17a Determine the slope function g (x). gʻ(x) = (x+1)2 17b Hence determine the slope at x = -2. gʻ(-2) = -5 17c Determine the equation of the tangent to the curve g(x) at x= -2. Leave your answer in the form y = mx+b. ☺ y-g(-2) =g'(-2)(x– (-2)) ???????

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Calculus Problem

**Problem Statement**

Consider the function \( g(x) = \frac{-2x + 3}{x + 1} \).

#### Part 17a

**Task:** Determine the slope function \( g'(x) \).

**Solution:** 

\[ g'(x) = -\frac{5}{(x + 1)^2} \]

_Solution is correct._

#### Part 17b

**Task:** Hence determine the slope at \( x = -2 \).

**Solution:**

\[ g'(-2) = -5 \]

_Solution is correct._

#### Part 17c

**Task:** Determine the equation of the tangent to the curve \( g(x) \) at \( x = -2 \). Leave your answer in the form \( y = mx + b \).

**Solution:**

\[ y - g(-2) = g'(-2) \left( x - (-2) \right) \]

_Solution is correct._

**Note:** The final equation of the tangent line is yet to be determined (indicated by "???????"). The remaining steps are likely to involve simplifying the equation and substituting values for \( g(-2) \), \( g'(-2) \), and \( x \).

### Summary

In this exercise, we:
1. Found the slope function \( g'(x) \) for a given rational function.
2. Evaluated the slope of the function at a specific point.
3. Set up the equation for the tangent line at this point.

This step-by-step approach is an excellent example of applying calculus concepts to find tangent lines and understanding the properties of functions.
Transcribed Image Text:### Calculus Problem **Problem Statement** Consider the function \( g(x) = \frac{-2x + 3}{x + 1} \). #### Part 17a **Task:** Determine the slope function \( g'(x) \). **Solution:** \[ g'(x) = -\frac{5}{(x + 1)^2} \] _Solution is correct._ #### Part 17b **Task:** Hence determine the slope at \( x = -2 \). **Solution:** \[ g'(-2) = -5 \] _Solution is correct._ #### Part 17c **Task:** Determine the equation of the tangent to the curve \( g(x) \) at \( x = -2 \). Leave your answer in the form \( y = mx + b \). **Solution:** \[ y - g(-2) = g'(-2) \left( x - (-2) \right) \] _Solution is correct._ **Note:** The final equation of the tangent line is yet to be determined (indicated by "???????"). The remaining steps are likely to involve simplifying the equation and substituting values for \( g(-2) \), \( g'(-2) \), and \( x \). ### Summary In this exercise, we: 1. Found the slope function \( g'(x) \) for a given rational function. 2. Evaluated the slope of the function at a specific point. 3. Set up the equation for the tangent line at this point. This step-by-step approach is an excellent example of applying calculus concepts to find tangent lines and understanding the properties of functions.
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