Consider the function f(x,y) %— ху — х -4 у a) The critical point of f is (х,у)- (4,1) b) According to the second derivative test, the critical point found in part a) yields A. saddle point B. local minimum C. inconclusive D. local maximum c) Consider the function f restricted to the region on the xy plane bounded by the triangle with vertices (0,4), (4,0) and (8,4). What is the absolute maximum and absolute minimum f takes on this region? Absolute max = 16 - 8 and occurs at the point ( 8', 4') Absolute min = - 16 and occurs at the point ( 0 , 4')
Consider the function f(x,y) %— ху — х -4 у a) The critical point of f is (х,у)- (4,1) b) According to the second derivative test, the critical point found in part a) yields A. saddle point B. local minimum C. inconclusive D. local maximum c) Consider the function f restricted to the region on the xy plane bounded by the triangle with vertices (0,4), (4,0) and (8,4). What is the absolute maximum and absolute minimum f takes on this region? Absolute max = 16 - 8 and occurs at the point ( 8', 4') Absolute min = - 16 and occurs at the point ( 0 , 4')
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Transcribed Image Text:Consider the function
f(x,y) — ху — х - 4 у
a) The critical point of f is
(ху)- (4,1)
b) According to the second derivative test, the critical point found in part a) yields
A. saddle point
B. local minimum
CC. inconclusive
D. local maximum
c) Consider the function f restricted to the region on the xy plane bounded by the triangle with vertices (0,4), (4,0) and (8,4).
What is the absolute maximum and absolute minimum f takes on this region?
Absolute max = 16 - 8 and occurs at the point ( 8', 4)
Absolute min =
- 16 and occurs at the point ( 0, 4)
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