Consider the function f(x, y) = 6y2 +4x2- 12xy- 4y. Then: O None of these O (1,-2/3) is a critical point and f has a saddle point at (-1,-2/3) O (1,1) is a critical point and f has a local maximum at (1,1) O (1,-2/3) is a critical point and f has a local minimum at (-1,-2/3)
Consider the function f(x, y) = 6y2 +4x2- 12xy- 4y. Then: O None of these O (1,-2/3) is a critical point and f has a saddle point at (-1,-2/3) O (1,1) is a critical point and f has a local maximum at (1,1) O (1,-2/3) is a critical point and f has a local minimum at (-1,-2/3)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![ONone of these
Consider the fimnction f(x,y) = 6y² + 4x² – 12xy-4y. Then:
O None of these
O (1,2/3) is a critical point and f has a saddle point at (-1,-2/3)
O (1,1) is a critical point and f has a local maximum at (1,1)
O (1,-2/3) is a critical point and f has a local minimum at (-1,-2/3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2f291caa-b2f6-4d37-b005-ceedd995ac12%2F8df46999-ee5a-4303-911b-2a42699fb290%2Fsg5g7r_processed.jpeg&w=3840&q=75)
Transcribed Image Text:ONone of these
Consider the fimnction f(x,y) = 6y² + 4x² – 12xy-4y. Then:
O None of these
O (1,2/3) is a critical point and f has a saddle point at (-1,-2/3)
O (1,1) is a critical point and f has a local maximum at (1,1)
O (1,-2/3) is a critical point and f has a local minimum at (-1,-2/3)
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