Consider the function f(x) = cos x - 3x + 1. Since f(0)f < 0, f(x) has a root in [0,. To solve f(x) = 0 using fixed-point method, we may consider the equivalent equation x = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point iteration xn = g(xn-1), with x = 0, will converge. What is x4? (Answer must be in 8 decimal places)
Consider the function f(x) = cos x - 3x + 1. Since f(0)f < 0, f(x) has a root in [0,. To solve f(x) = 0 using fixed-point method, we may consider the equivalent equation x = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point iteration xn = g(xn-1), with x = 0, will converge. What is x4? (Answer must be in 8 decimal places)
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter4: Exponential And Logarithmic Functions
Section: Chapter Questions
Problem 3CC: If xis large, which function grows faster, f(x)=2x or g(x)=x2?
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![Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ (1) < 0. f(x) has a root in
-
[0]. To solve f(x) = 0 using fixed-point method, we may consider the equivalent
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equation x = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point
iteration xn = g(xn-1), with xo = 0, will converge. What is x4? (Answer must be in 8
decimal places)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1262d5e8-5166-4b09-b60d-001c2100a91a%2F2d5f6f2e-2480-41b7-b5c7-3b502ee2dfac%2Fkh0be6b_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ (1) < 0. f(x) has a root in
-
[0]. To solve f(x) = 0 using fixed-point method, we may consider the equivalent
J
equation x = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point
iteration xn = g(xn-1), with xo = 0, will converge. What is x4? (Answer must be in 8
decimal places)
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