Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ () <0. f(x) has a root in [0]. If we use secant method, with x。 = 0.5 and x₁ = 0.6, to estimate the root of f(x) = cos x − 3x + 1, what is x3? (Answer must be in 8 decimal places)
Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ () <0. f(x) has a root in [0]. If we use secant method, with x。 = 0.5 and x₁ = 0.6, to estimate the root of f(x) = cos x − 3x + 1, what is x3? (Answer must be in 8 decimal places)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 21T
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![Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ () <0. f(x) has a root in
[0]. If we use secant method, with x。 = 0.5 and x₁ = 0.6, to estimate the root of
f(x) = cos x − 3x + 1, what is x3? (Answer must be in 8 decimal places)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3575351d-1f4c-4382-8c20-dcea0980df10%2Fbf0c3c7a-6175-4461-b058-826356d94a95%2F2hx9n3b_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ () <0. f(x) has a root in
[0]. If we use secant method, with x。 = 0.5 and x₁ = 0.6, to estimate the root of
f(x) = cos x − 3x + 1, what is x3? (Answer must be in 8 decimal places)
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