Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ (-) < 0, ƒ (x) has a root in [0, 1]. To solve f(x) = 0 using fixed-point method, we may consider the equivalent equation x = = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point iteration x₂ = g(xn-1), with xo = 0, will converge. What is x4? (Answer must be in 8 decimal places)
Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ (-) < 0, ƒ (x) has a root in [0, 1]. To solve f(x) = 0 using fixed-point method, we may consider the equivalent equation x = = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point iteration x₂ = g(xn-1), with xo = 0, will converge. What is x4? (Answer must be in 8 decimal places)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ (-) < 0, ƒ (x) has a root in
[0, 1]. To solve f(x) = 0 using fixed-point method, we may consider the equivalent
equation x = = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point
iteration x₂ = g(xn-1), with xo = 0, will converge. What is x4? (Answer must be in 8
decimal places)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3575351d-1f4c-4382-8c20-dcea0980df10%2F72f9ee48-be4a-47bd-bddb-fb2a1aaadc65%2Fu5i2xr_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the function f(x) = cos x − 3x + 1. Since ƒ (0)ƒ (-) < 0, ƒ (x) has a root in
[0, 1]. To solve f(x) = 0 using fixed-point method, we may consider the equivalent
equation x = = (1 + cos x). Let g(x) = (1 + cos x). Since [g'(0)| < 1, the fixed-point
iteration x₂ = g(xn-1), with xo = 0, will converge. What is x4? (Answer must be in 8
decimal places)
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