Consider the function f(x) = 6 - 3x² on the interval [-6, 7]. Find the average or mean slope of the function on this interval, i.e. f(7)-f(-6) 7-(-6) By the Mean Value Theorem, we know there exists a c in the open interval (-6, 7) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. Find it.

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A: f(x)=13x-5Domain is -3,0,6substitute x=-3f(-3)=13(-3)-5=1-9-5=-114

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Q: Differentiate. f(x) = In (4x + 1)(x+7)³ (1 - 6x)5

A: The solution is given below: