● · Consider the function f(x) = 4 sin ((x-3) +6. State the amplitude A, period P, and midline. State the phase shift and vertical translation. In the full period [0, P], state the maximum and minimum y-values and their corresponding -values. Hints for the maximum and minimum values of f(x): The maximum value of y = sin(x) is y = 1 and the corresponding a values are x = than this a value. You may want to solve (x − 3) = 2 x = y = Enter the exact answers. Amplitude: A = Period: P Midline: y x = The phase shift is The vertical translation is y = • For x in the interval [0, P], the maximum y-value and corresponding c-value is at: • The minimum value of y = sin(x) is y = -1 and the corresponding a values are x = 3 T 2 For x in the interval [0, P], the minimum y-value and corresponding x-value is at: and multiples of 2 π less than and mor more than this à value. You may want to solve (x − 3) = 3″ 2 If you get a value for a that is less than 0, you could add multiples of P to get into the next cycles. If you get a value for x that is more than P, you could subtract multiples of P to get into the previous cycles. and multiples of 2 π less than an Cho mlovala na show Bus
● · Consider the function f(x) = 4 sin ((x-3) +6. State the amplitude A, period P, and midline. State the phase shift and vertical translation. In the full period [0, P], state the maximum and minimum y-values and their corresponding -values. Hints for the maximum and minimum values of f(x): The maximum value of y = sin(x) is y = 1 and the corresponding a values are x = than this a value. You may want to solve (x − 3) = 2 x = y = Enter the exact answers. Amplitude: A = Period: P Midline: y x = The phase shift is The vertical translation is y = • For x in the interval [0, P], the maximum y-value and corresponding c-value is at: • The minimum value of y = sin(x) is y = -1 and the corresponding a values are x = 3 T 2 For x in the interval [0, P], the minimum y-value and corresponding x-value is at: and multiples of 2 π less than and mor more than this à value. You may want to solve (x − 3) = 3″ 2 If you get a value for a that is less than 0, you could add multiples of P to get into the next cycles. If you get a value for x that is more than P, you could subtract multiples of P to get into the previous cycles. and multiples of 2 π less than an Cho mlovala na show Bus
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![●
Consider the function f(x) = 4 sin((x-3) +6. State the amplitude A, period P, and midline. State the phase shift and vertical
translation. In the full period [0, P], state the maximum and minimum y-values and their corresponding a-values.
Hints for the maximum and minimum values of f(x):
The maximum value of y = sin(x) is y = 1 and the corresponding a values are x =
than this a value. You may want to solve (x − 3) = 2
x =
y =
Enter the exact answers.
Amplitude: A =
Period: P
Midline: y
The phase shift is
The vertical translation is
x =
y =
•
For x in the interval [0, P], the maximum y-value and corresponding c-value is at:
•
The minimum value of y = sin(x) is y = -1 and the corresponding a values are x =
3 п
more than this a value. You may want to solve(x-3) = 2
For x in the interval [0, P], the minimum y-value and corresponding x-value is at:
and multiples of 2 π less than and more
3 T
2
If you get a value for a that is less than 0, you could add multiples of P to get into the next cycles.
If you get a value for x that is more than P, you could subtract multiples of P to get into the previous cycles.
and multiples of 2 π less than and
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Transcribed Image Text:●
Consider the function f(x) = 4 sin((x-3) +6. State the amplitude A, period P, and midline. State the phase shift and vertical
translation. In the full period [0, P], state the maximum and minimum y-values and their corresponding a-values.
Hints for the maximum and minimum values of f(x):
The maximum value of y = sin(x) is y = 1 and the corresponding a values are x =
than this a value. You may want to solve (x − 3) = 2
x =
y =
Enter the exact answers.
Amplitude: A =
Period: P
Midline: y
The phase shift is
The vertical translation is
x =
y =
•
For x in the interval [0, P], the maximum y-value and corresponding c-value is at:
•
The minimum value of y = sin(x) is y = -1 and the corresponding a values are x =
3 п
more than this a value. You may want to solve(x-3) = 2
For x in the interval [0, P], the minimum y-value and corresponding x-value is at:
and multiples of 2 π less than and more
3 T
2
If you get a value for a that is less than 0, you could add multiples of P to get into the next cycles.
If you get a value for x that is more than P, you could subtract multiples of P to get into the previous cycles.
and multiples of 2 π less than and
facere noe sow juby
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