Consider the function f(x) = 4 – 7², - 5 < x < 1. The absolute maximum value is and this occurs at x The absolute minimum value is and this occurs at x =

Let f (x) = 4x+ 9x - 12x + 5. Find the absolute minimum value of f on the interval [0, 3]. You will find that the the absolute minimum value of f on [0, 3] is f (c) for some number o in 10, 3and you should type the value of f(c).

Consider the function f(x) = 2 – 2x², – 3 < x < 1. The absolute maximum value is and this occurs at x = The absolute minimum value is and this occurs at x =