Consider the function f(x) = -3x²³ +3x²-3x -\ Find average rate of change on interval (-4,-1). Find the C in the interval which works.

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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**Mathematical Analysis on Functions**

### Problem Statement

Consider the function \( f(x) = -3x^3 + 3x^2 - 3x - 1 \).

1. Find the average rate of change on the interval \([-4, -1]\).
2. Find the \( c \) in the interval which works.

### Detailed Explanation

To find the average rate of change of the function \( f(x) \) over the interval \([-4, -1]\), we use the formula:

\[
\text{Average rate of change} = \frac{f(b) - f(a)}{b - a}
\]

where \( a \) and \( b \) are the endpoints of the interval \([-4, -1]\).

1. **Calculate \( f(-4) \) and \( f(-1) \)**:
    - \( f(-4) = -3(-4)^3 + 3(-4)^2 - 3(-4) - 1 \)
    - \( f(-1) = -3(-1)^3 + 3(-1)^2 - 3(-1) - 1 \)

2. **Plug the values into the average rate of change formula**:
    - \( \text{Average rate of change} = \frac{f(-1) - f(-4)}{-1 - (-4)} \)

Next, identify the value of \( c \) within the interval \([-4, -1]\) that satisfies the Mean Value Theorem, if applicable. For this, ensure the first derivative \( f'(x) \) exists and is continuous over the interval. Verify \( f'(c) = \text{average rate of change} \).

### Diagram Explanation

While this problem does not include specific graphs or diagrams, plotting \( f(x) \) along with its derivative \( f'(x) \) over the interval \([-4, -1]\) would greatly aid in visualizing changes and confirming the solutions.
Transcribed Image Text:**Mathematical Analysis on Functions** ### Problem Statement Consider the function \( f(x) = -3x^3 + 3x^2 - 3x - 1 \). 1. Find the average rate of change on the interval \([-4, -1]\). 2. Find the \( c \) in the interval which works. ### Detailed Explanation To find the average rate of change of the function \( f(x) \) over the interval \([-4, -1]\), we use the formula: \[ \text{Average rate of change} = \frac{f(b) - f(a)}{b - a} \] where \( a \) and \( b \) are the endpoints of the interval \([-4, -1]\). 1. **Calculate \( f(-4) \) and \( f(-1) \)**: - \( f(-4) = -3(-4)^3 + 3(-4)^2 - 3(-4) - 1 \) - \( f(-1) = -3(-1)^3 + 3(-1)^2 - 3(-1) - 1 \) 2. **Plug the values into the average rate of change formula**: - \( \text{Average rate of change} = \frac{f(-1) - f(-4)}{-1 - (-4)} \) Next, identify the value of \( c \) within the interval \([-4, -1]\) that satisfies the Mean Value Theorem, if applicable. For this, ensure the first derivative \( f'(x) \) exists and is continuous over the interval. Verify \( f'(c) = \text{average rate of change} \). ### Diagram Explanation While this problem does not include specific graphs or diagrams, plotting \( f(x) \) along with its derivative \( f'(x) \) over the interval \([-4, -1]\) would greatly aid in visualizing changes and confirming the solutions.
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