Consider the function f(x) = 2x³ - 27x² 60x-10, -5≤x≤ 15. The absolute minimum of f(x) (on the given interval) is at x = and the absolute minimum of f(x) (on the given interval) is The absolute maximum of f(x) (on the given interval) is at X = and the absolute maximum of f(x) (on the given interval) is (Note: If a function has two x values at which a maxima or minima occur, enter them both separated by a comma.)

College Algebra
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Chapter2: Functions And Their Graphs
Section2.4: A Library Of Parent Functions
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9.2)
Consider the function f(x) = 2x³ - 27x² - 60x-10, -5 ≤x≤15.
The absolute minimum of f(x) (on the given interval) is at
X =
and the absolute minimum of f(x) (on the given interval) is
The absolute maximum of f(x) (on the given interval) is at
x =
and the absolute maximum of f(x) (on the given interval) is
(Note: If a function has two x values at which a maxima or minima occur, enter them both separated by
a comma.)
Transcribed Image Text:Consider the function f(x) = 2x³ - 27x² - 60x-10, -5 ≤x≤15. The absolute minimum of f(x) (on the given interval) is at X = and the absolute minimum of f(x) (on the given interval) is The absolute maximum of f(x) (on the given interval) is at x = and the absolute maximum of f(x) (on the given interval) is (Note: If a function has two x values at which a maxima or minima occur, enter them both separated by a comma.)
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