Consider the function f: Z→ Z, n→ T 3+12n 4 Note: denotes the ceiling function. Which of the following is true? f is not injective but is surjective Of is bijective. f is neither injective nor surjective. f is injective but is not surjective.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Question
Consider the function
f: Z→Z, n
3+12n
4
Note: [] denotes the ceiling function.
Which of the following is true?
Of is not injective but is surjective
Of is bijective.
Of is neither injective nor surjective.
Of is injective but is not surjective.
Transcribed Image Text:Consider the function f: Z→Z, n 3+12n 4 Note: [] denotes the ceiling function. Which of the following is true? Of is not injective but is surjective Of is bijective. Of is neither injective nor surjective. Of is injective but is not surjective.
Expert Solution
Step 1: The Ceiling Function

The Ceiling Function is defined as the smallest integer that is not smaller than x. It is the opposite of The Floor Function or the Greatest Integer function. It is denoted by open ceil x close ceil

For example open ceil 4.5 close ceil space i s space 5  whereas open floor 4.5 close floor space i s space 4.

The given function is 

D e f i n e space a space f u n c t i o n space f colon space straight integer numbers rightwards arrow straight integer numbers space space b y space n rightwards arrow from bar open ceil fraction numerator 3 plus 12 n over denominator 4 end fraction close ceil
f open parentheses n close parentheses equals open ceil fraction numerator 3 plus 12 n over denominator 4 end fraction close ceil
f open parentheses n close parentheses equals open ceil 0.75 plus 3 n close ceil
f open parentheses n close parentheses equals 3 n plus 1

Check injective f is one one function if f open parentheses x close parentheses equals f open parentheses y close parentheses rightwards double arrow x equals y

Check surjective f colon space A rightwards arrow B is onto function if for every y element of B space there exists space x element of A space s u c h space t h a t space f open parentheses x close parentheses equals y

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