Finite Mathematics **Consider the following:****(a)** In how many different ways can a player select a *diamond* and a *spade* from a deck of 52 bridge cards?- Answer: 2652 ways (Incorrect)**(b)** In how many different ways can a player select one card of each suit from a bridge deck?- Answer: 2704 ways (Incorrect)**Additional Materials:**- [eBook Link]**Navigation:**- View Previous Question- Question 8 of 20- View Next Question**Footer:**- Home- My Assignments**Image Description:**The image displays a few decks of cards with four cards spread out, showing the ace of diamonds, ace of spades, ace of hearts, and ace of clubs.

Name: Finite Mathematics **Consider the following:****(a)** In how many diff
Uploaded: 2024-03-20T06:38:44.000Z
Channel: Bartleby
Description: Finite Mathematics **Consider the following:****(a)** In how many different ways can a player select a *diamond* and a *spade* from a deck of 52 bridge cards?- Answer: 2652 ways (Incorrect)**(b)** In how many different ways can a player select one ca

The total number of ways selecting 2 cards is, C252=52!2!52-2!=52×51×50!2!×50!=1275To calculate how many different ways can a players select a diamond and a spade from a deck of 52 bridge cards, The total number of selecting a diamond is C113 Similarly the total number of ways of selecting a spade is C113 Hence the total number of different ways can players selects a diamond and a spade from a deck of 52 bridge cards, =13C1×13C1=13×13=169 Therefore 169 ways can players selects a diamond and a spade from a deck of 52 bridge cardsB) Each suit contains 13 cards. Select one card is C113=13 Total 4 suits, so select one card from each suit is, =13C1×13C1×13C1×13C1=13×13×13×13=28561