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Consider the following. 1x D xy dA, D is enclosed by the curves y = x², y Express D as a region of type I. OD = {(x, y) | 0 ≤ x ≤ 4, x² ≤ y ≤ 2x} D = {(x, y) | 0 ≤ x ≤ 2, x² ≤ y ≤ 2x} OD = {(x, y) | 0≤x≤ 4, x² ≤ y ≤ 4x} D= •OD = {(x, y) | 2 ≤ x ≤ 4, x² ≤ y ≤ 4x} D = {(x, y) | 0 ≤ x ≤y, x² ≤ y ≤ 2} Express D as a region of type II. D = = {(x, y) 10 ≤ y ≤ 2, 1/2 ≤ √x ≤ √y} OD= = {(x, y) 10 ≤ y ≤ 2, 1/ sxs √y} 4 = {(x, y) 10 ≤ y ≤ 4, 1/1/2 >= {(x, y) 10 ≤ y ≤ 4, SXS √r} X 5 = = √V }

Consider the following. 1x D xy dA, D is enclosed by the curves y = x², y Express D as a region of type I. OD = {(x, y) | 0 ≤ x ≤ 4, x² ≤ y ≤ 2x} D = {(x, y) | 0 ≤ x ≤ 2, x² ≤ y ≤ 2x} OD = {(x, y) | 0≤x≤ 4, x² ≤ y ≤ 4x} D= •OD = {(x, y) | 2 ≤ x ≤ 4, x² ≤ y ≤ 4x} D = {(x, y) | 0 ≤ x ≤y, x² ≤ y ≤ 2} Express D as a region of type II. D = = {(x, y) 10 ≤ y ≤ 2, 1/2 ≤ √x ≤ √y} OD= = {(x, y) 10 ≤ y ≤ 2, 1/ sxs √y} 4 = {(x, y) 10 ≤ y ≤ 4, 1/1/2 >= {(x, y) 10 ≤ y ≤ 4, SXS √r} X 5 = = √V }

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the following. Express D as a region of type I. D = {(x, y) | 0 ≤ x ≤ 4, x² ≤ y ≤ 2x} Jxy da, xy dA, D is enclosed by the curves y = x², y = 2x D {(x, y) |0 ≤ x ≤ 0 = {(x, y) | 0 ≤ x ≤ 4, x² ≤ y ≤ 4x} {(x, y) | 2 ≤ x ≤ 4, x² ≤ y ≤ 4x} D = {(x, y) | 0 ≤ x ≤y, x² ≤ y ≤ 2} = 2, x² ≤ y ≤ 2x} Express D as a region of type II. D= D= = {(x, y) 10 ≤ y ≤ 2, 1/2 ≤ √x ≤ √Y} S y {(x, y) 10 ≤ y ≤ 2, 1 ≤ x ≤ √V } S 4 y D = {(x, y) 10 ≤ y ≤ 4, 1/2 sxs sxsv D >= {(x, y) 10 ≤ y ≤ 4, 1/5 2 4 X S = √Y} D = {(x, y) 10 ≤ y ≤ 2,0 ≤ x ≤ 4} Evaluate the double integral in two ways.
Transcribed Image Text:Consider the following. Express D as a region of type I. D = {(x, y) | 0 ≤ x ≤ 4, x² ≤ y ≤ 2x} Jxy da, xy dA, D is enclosed by the curves y = x², y = 2x D {(x, y) |0 ≤ x ≤ 0 = {(x, y) | 0 ≤ x ≤ 4, x² ≤ y ≤ 4x} {(x, y) | 2 ≤ x ≤ 4, x² ≤ y ≤ 4x} D = {(x, y) | 0 ≤ x ≤y, x² ≤ y ≤ 2} = 2, x² ≤ y ≤ 2x} Express D as a region of type II. D= D= = {(x, y) 10 ≤ y ≤ 2, 1/2 ≤ √x ≤ √Y} S y {(x, y) 10 ≤ y ≤ 2, 1 ≤ x ≤ √V } S 4 y D = {(x, y) 10 ≤ y ≤ 4, 1/2 sxs sxsv D >= {(x, y) 10 ≤ y ≤ 4, 1/5 2 4 X S = √Y} D = {(x, y) 10 ≤ y ≤ 2,0 ≤ x ≤ 4} Evaluate the double integral in two ways.
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