Consider the following Venn Diagram, which was constructed based on the data from a survey of 222 UNLV students about whether or not they had any of the three social media accounts.[Image: Venn Diagram showing the distribution of social media accounts among UNLV students]**Venn Diagram Explanation:**- **Facebook:** - Total with Facebook accounts: 46 - Facebook and Instagram only: 23 - Facebook and Twitter only: 24 - All three accounts (Facebook, Instagram, Twitter): 2- **Instagram:** - Total with Instagram accounts: 50 - Instagram and Facebook only: 23 - Instagram and Twitter only: 23 - All three accounts (Facebook, Instagram, Twitter): 2- **Twitter:** - Total with Twitter accounts: 37 - Twitter and Facebook only: 24 - Twitter and Instagram only: 23 - All three accounts (Facebook, Instagram, Twitter): 2- **Only Instagram:** 17**Questions:**a) What is the probability that a UNLV student **has a Facebook account, but not a Twitter account**? (Round your answer to four decimal places before entering in the box below).[Input Box]b) What is the probability that a UNLV student **has both Instagram AND Twitter accounts, but not a Facebook account**? (Round your answer to four decimal places before entering in the box below).[Input Box]

a)The Venn diagram of total 222 students, who have any of the three social media accounts, is…

Answered: Consider the following Venn Diagram,…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A manager at your local VA hospital records the following table regarding patients seen on a given day with respect to blood type. Totals Blood Type Blood type Blood type A B AB O total 456 895 1,775 1,976 5,102 A) What is the probability of a patient having blood type O on this given day? B) What is the probability of a patient having blood type A or B on this given day?
The following table describes the smoking habits of a group of asthma sufferers Nonsmoker (NS) Smoker (S) Men (M) 275 50 Women (W) 147 30 If one of the peopleis randomly selected, what is the probability the subject is a smoker or a woman?
Real estate ads suggest that 50 % of homes for sale have garages, 38 % have swimming pools, and 33 % have both features. What is the probability that a home for sale has a) a pool or a garage? Answer = 55 % b) neither a pool nor a garage? Answer = 45 % c) a pool but no garage? Answer = 05 Set up a Venn diagram to correctly illustrate the problem. Show how to use the Venn diagram with your given probabilities to get each of your solutions. %3D
According to reports, 30% of American adults have chronic insomnia. If 3 American adults are chosen at random, what is the probability that all 3 have chronic insomnia? A) 0.90 B) 0.027 C) 0.093 D) 0.075 E) 0.8437
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All students in a high school were surveyed about two sports. The results are shown in the graph. Frequency 600 400 200 0 190 Sports Survey 565 Basketball 340 Football Like Basketball or Football Both 100 Neither a) How many students were surveyed? b) What is the probability that a student (chosen at random) likes only basketball? Express your answer as a decimal, rounded to 2 decimal places. c) What is the probability that a student (chosen at random) likes both basketball and football? Express your answer as a percentage. d) What is the probability that a student (chosen at random) likes neither basketball nor football? Express your answer as a fraction in lowest terms.
Need help pls!
A Gallup poll of 1,236 adults showed that 14% believe that bad luck follows if your path is crossed by a black cat. a) Find u, o?, o, and usual values. b) Use the above information to find the probability that a total of 203 subjects believe that bad luck follows if your path is crossed by a black cat. a) Use the above information to find the probability that less than 203 subjects believe that bad luck follows if your path is crossed by a black cat.
Please Answer d). & e). Only The contingency table below shows the results of a survey of video viewing habits by age. Video Viewing Platform Preferred Viewer Age Mobile/Laptop Device TV Screen Row Total 18–34 40 23 63 35–54 12 12 24 55+ 5 8 13 Column Total 57 43 100 Find the following probabilities or percentages: (a) Probability that a viewer is aged 18–34. (Round your answer to 2 decimal places.) Probability (b) Probability that a viewer prefers watching videos on a TV screen. (Round your answer to 2 decimal places.) Probability (c) Percentage of viewers who are 18–34 and prefer videos on a mobile or laptop device. Percentage of viewers % (d) Percentage of viewers given they are 18–34 who prefer videos on a mobile or laptop device. (Round your answer to 2 decimal places.) Percentage of viewers % (e) Percentage of viewers who are 35–54…
All students in a high school were surveyed about two sports. The results are shown in the graph. Frequency 600 400 200 0 190 Sports Survey 565 Basketball 340 Football Like Basketball or Football Both 100 Neither a) How many students were surveyed? b) What is the probability that a student (chosen at random) likes only basketball? Express your answer as a decimal, rounded to 2 decimal places. c) What is the probability that a student (chosen at random) likes both basketball and football? Express your answer as a percentage. d) What is the probability that a student (chosen at random) likes neither basketball nor football? Express your answer as a fraction in lowest terms.
3. The latest data from the CDC indicates that 14% of Americans are smokers. A researcher wants to identify smokers for a survey. He randomly selects people entering a grocery store to ask if they are a smoker. a) What is the probability that he identifies the first smoker on his 5th try? b) What is the probability that he has to approach more than 8 people before finding the first smoker? c) How many people does he expect to approach before finding the first smoker?
In 2014, the percentage of the U.S. population that speak English only in the home is 78.9%. Choose 15 U.S. people at random. What is the probability that exactly one-third of them speak English only? At least one-third? What is the probability that at least 9 do not speak English in the home?

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