Consider the following system of linear equations. 4x-8y=-12 -4x+10y = 12 Solve the system by completing the steps below to produce a reduced row-echelon form. R₁ and R₂ denote the first and second rows, respectively. The arrow notation (→) means the expression/matrix on the left becomes the expression/matrix on the right once the row operations are performed. (a) For each step below, enter the coefficient for the row operation. The first matrix in Step 1 is the augmented matrix for the given system of equations. Step 1: 4 -8 -4 10 Step 2: -2 !-3 [32] -4 10 12 Step 3: X - 12 12 -2 ! -3 2 -2 ! 1 [23] Step 4: Enter the coefficient for the row operations and the missing entries in the resulting matrix. 0 0 (b) Give the solution. -0 R₁ → R₁ R₁ + R₂ R₂ y = [.R₂ → R₂ 0-4 R₂ + R₁ R₁ -2 43 10 12 -2 [213] 0 0 0 [19 olo X

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