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Consider the following system at equilibrium where AH° = 16.1 kJ, and K. = 6.50x103, at 298 K. 2NOBr(g) =2NO(g) + Br2(g) When 0.15 moles of NO(g) are added to the equilibrium system at constant temperature: The value of K. The value of Qc. V Kc. The reaction must O run in the forward direction to restablish equilibrium. O run in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of Br, will

Consider the following system at equilibrium where AH° = 16.1 kJ, and K. = 6.50x103, at 298 K. 2NOBr(g) =2NO(g) + Br2(g) When 0.15 moles of NO(g) are added to the equilibrium system at constant temperature: The value of K. The value of Qc. V Kc. The reaction must O run in the forward direction to restablish equilibrium. O run in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of Br, will

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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help me asap pls for number 6 i'll give you an upvote later

Consider the following system at equilibrium where AH° = 16.1 kJ, and K. = 6.50x103, at 298 K. 2NOBr(g) =2NO(g) + Br2(g) When 0.15 moles of NO(g) are added to the equilibrium system at constant temperature: The value of K. The value of Qc. V Kc. The reaction must O run in the forward direction to restablish equilibrium. O run in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of Br, will
Transcribed Image Text:Consider the following system at equilibrium where AH° = 16.1 kJ, and K. = 6.50x103, at 298 K. 2NOBr(g) =2NO(g) + Br2(g) When 0.15 moles of NO(g) are added to the equilibrium system at constant temperature: The value of K. The value of Qc. V Kc. The reaction must O run in the forward direction to restablish equilibrium. O run in the reverse direction to restablish equilibrium. O remain the same. It is already at equilibrium. The concentration of Br, will
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