Consider the following steps in 2 differentiating f(x) = ln x² sin 2x Identify the line number where the FIRST ERROR occurred. f'(x) = 2ln .D. [In (sin ²2r)] sin 2r (1) f'(x) = 2ln -D₂ (2)] sin 2x (2) sin 2r 2² 27). [(sin 2x).. · [(sin2x).((^ f'(x) = 2ln 2)D, (sin 2r))] sin 2x (3) f'(x) = 2ln (Sim2). [(Sin 2²r) (sin 2r) D. (2²) — (1³)D, (sin 2r)` sin² 2.x (²) (cos 2x)\ sin² 22 (sin 2x) (2x) sin 2)(cus 2x))] O Line (1) 3

Calculus: Early Transcendentals
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Author:James Stewart
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Consider the following steps in
2
differentiating f(x) = ln
x²
sin 2x
Identify the line number where the FIRST
ERROR occurred.
f'(x) = 2ln
.D. [In (sin ²2r)]
sin 2r
(1)
f'(x) = 2ln
-D₂
(2)]
(2)
sin 2x
sin 2r
2²
27). [(sin 2x)..
· [(sin2x).((^
f'(x) = 2ln
2)D, (sin 2r))]
sin 2x
(3)
f'(x) = 2ln (Sim2). [(Sin 2²r)
(sin 2r) D. (2²) — (1³)D, (sin 2r)`
sin² 2.x
(²) (cos 2x)\
sin² 22
(sin 2x) (2x)
sin
2)(cus 2x))]
O Line (1)
O Line (2)
O Line (3)
O Line (4)
O All of the above
O None of the above
Transcribed Image Text:Consider the following steps in 2 differentiating f(x) = ln x² sin 2x Identify the line number where the FIRST ERROR occurred. f'(x) = 2ln .D. [In (sin ²2r)] sin 2r (1) f'(x) = 2ln -D₂ (2)] (2) sin 2x sin 2r 2² 27). [(sin 2x).. · [(sin2x).((^ f'(x) = 2ln 2)D, (sin 2r))] sin 2x (3) f'(x) = 2ln (Sim2). [(Sin 2²r) (sin 2r) D. (2²) — (1³)D, (sin 2r)` sin² 2.x (²) (cos 2x)\ sin² 22 (sin 2x) (2x) sin 2)(cus 2x))] O Line (1) O Line (2) O Line (3) O Line (4) O All of the above O None of the above
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