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Consider the following statements: T(x, y): "x eats y". A(x): "x is wise". S(x): "x is hungry". F(y): "y is fat". H(y): "y is healthy". The domain of x is the set of all people and the domain of y is the set of all food. Select the symbolic of the following sentence (one or more answers): "All healthy food are eaten by all wise people" Vx Vy -T(x,y) →A (x) V H (y) Vx Vy T(x,y)→¬A (x) V ¬H (y) None of all proposed answers Vx Vy -T(x,y) → ¬A (x) V ¬H (y) Vx Vy -T(x,y) v ¬A (x) V ¬H (y)

Consider the following statements: T(x, y): "x eats y". A(x): "x is wise". S(x): "x is hungry". F(y): "y is fat". H(y): "y is healthy". The domain of x is the set of all people and the domain of y is the set of all food. Select the symbolic of the following sentence (one or more answers): "All healthy food are eaten by all wise people" Vx Vy -T(x,y) →A (x) V H (y) Vx Vy T(x,y)→¬A (x) V ¬H (y) None of all proposed answers Vx Vy -T(x,y) → ¬A (x) V ¬H (y) Vx Vy -T(x,y) v ¬A (x) V ¬H (y)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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QUESTION 12 Consider the following statements: Tx, у): "х еats y". A(x): "x is wise". S(x): "x is hungry". F(y): "y is fat". H(y): "y is healthy". The domain of x is the set of all people and the domain of y is the set of all food. Select the symbolic of the following sentence (one or more answers): "All healthy food are eaten by all wise people" Vx Vy -T(x,y) →A (x) V H (y) Vx Vy T(x,у) — (х) V -Н(у) None of all proposed answers Vx Vy -T(x,y) → ¬A (x) V ¬H (y) Vx Vy -T(x,y) v ¬A (x) V ¬H(y)
Transcribed Image Text:QUESTION 12 Consider the following statements: Tx, у): "х еats y". A(x): "x is wise". S(x): "x is hungry". F(y): "y is fat". H(y): "y is healthy". The domain of x is the set of all people and the domain of y is the set of all food. Select the symbolic of the following sentence (one or more answers): "All healthy food are eaten by all wise people" Vx Vy -T(x,y) →A (x) V H (y) Vx Vy T(x,у) — (х) V -Н(у) None of all proposed answers Vx Vy -T(x,y) → ¬A (x) V ¬H (y) Vx Vy -T(x,y) v ¬A (x) V ¬H(y)
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