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Consider the following script: x = 0:0.1:2; for i - 1:length (x) y (i) = sin (2*pi*x(i)) *exp(-0.5*x (i)); end Setting aside the loop variable, which single statement below is equivalent to the entire for loop above? Select one: O a. y - sin (2*pi*x) *exp (-0.5*x); cross out O b. for y - sin (2*pi*x) *exp (-0.5 eross out O c. y - sin (2*pi*x).*exp (-0.5*x); cross out O d. for y = sin (2*pi*x).*exp(-0.5 COSs out O e. This loop cannot cross out be vectorized

Consider the following script: x = 0:0.1:2; for i - 1:length (x) y (i) = sin (2*pi*x(i)) *exp(-0.5*x (i)); end Setting aside the loop variable, which single statement below is equivalent to the entire for loop above? Select one: O a. y - sin (2*pi*x) *exp (-0.5*x); cross out O b. for y - sin (2*pi*x) *exp (-0.5 eross out O c. y - sin (2*pi*x).*exp (-0.5*x); cross out O d. for y = sin (2*pi*x).*exp(-0.5 COSs out O e. This loop cannot cross out be vectorized

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Consider the following script: x = 0:0.1:2; for i = 1:length (x) y (i) = sin (2*pi*x(i)) *exp(-0.5*x (i)); end Setting aside the loop variable, which single statement below is equivalent to the entire for loop above? Select one: y = sin (2*pi*x) *exp (-0.5*x); cross out а. b. for y - sin (2*pi*x) *exp (-0.5*eross out C. sin (2*pi*x). *exp (-0.5*x); cross out O d. for y = sin (2*pi*x). *exp (-0.5 CKOss out e. This loop cannot cross out be vectorized
Transcribed Image Text:Consider the following script: x = 0:0.1:2; for i = 1:length (x) y (i) = sin (2*pi*x(i)) *exp(-0.5*x (i)); end Setting aside the loop variable, which single statement below is equivalent to the entire for loop above? Select one: y = sin (2*pi*x) *exp (-0.5*x); cross out а. b. for y - sin (2*pi*x) *exp (-0.5*eross out C. sin (2*pi*x). *exp (-0.5*x); cross out O d. for y = sin (2*pi*x). *exp (-0.5 CKOss out e. This loop cannot cross out be vectorized
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