Consider the following regression results:ŷ = 4.5 -2.8x1 + 1.2x2 + 1.1x3,(1.8) (-7)(1.2)(1.5)n = 19, R² = .55.The minimum significance level that we can reject the null hypothesis that B₁ = -2 (two-tailed test) is at the1% significance level.5% significance level.10% significance level.None of the above.

Null Hypothesis: β1=-2 Alternative Hypothesis: β1≠-2 From the equation, Coefficient of X1 is -2.8…

Answered: Consider the following regression…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Based on the regression output below, which of the following are correlated with satisfaction (using a 95% confidence level)? Correlations N=253 322-Satisfaction X15-Fresh Food X18-Excellent Food Taste Pearson Correlation X20-Proper Food Pearson Correlation (2-talled) Pearson Correlation X22- Satisfaction 1 627" 000 393 Sig (2-tailed) Pearson Correlation Sig (2-talled) *Correlation is significant at the 0.01 level (2-tailed). 000 430" 000 X15-Fresh Food 27 000 1 770" 000 686* 000 X18-Excellent Food Taste 393* ,000 770* 000 1 721 000 X20-Proper Food Temperature 430* ,000 686 000 721" 000 1
additionally does this reject the null hypothesis
Consider a regression analysis with n = 47 and three potential independent variables. Suppose that one of the independent variables has a correlation of 0.95 with the dependent variable. Does this imply that this independent variable will have a very large Student’s t statistic in the regression analysis with all three predictor variables?
Consider the following regression results: i = 4.5 2.821 + 1.2a2 + 1.1a3. (1.8) (.7) (1.2) (1.6) 19, R = .55. 723D %3D The minimum significance level that we can reject the null hypothesis that B1 =-2 (two-tailed test) is at the %3D 5% significance level. O 10% significance level. O None of the above. O 1% significance level.
You wish to test the following claim (HaHa) at a significance level of α=0.05 Ho:μ1=μ2 Ha:μ1≠μ2You believe both populations are normally distributed, but you do not know the standard deviations for either. However, assume that the variances of the two populations are equal. You obtain a sample of size n1=23 with a mean of ¯x1=74.5 and a standard deviation of SD1=20.4 from the first population. You obtain a sample of size n2=11with a mean of ¯x2=89.8and a standard deviation of SD2=7.3 from the second population.What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) αα greater than αα This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of…
The table below lists weights (carats) and prices (dollars) of randomly selected diamonds. Find the (a) explained variation, (b) unexplained variation, and (c) indicated prediction interval. There is sufficient evidence o support a claim of a linear correlation, so it is reasonable to use the regression equation when making predictions. For the prediction interval, use a 95% confidence level with a diamond that weighs 0.8 carats. Weight Price 0.3 $508 a. Find the explained variation. 0.4 $1153 0.5 $1332 Round to the nearest whole number as needed.) . Find the unexplained variation. Round to the nearest whole number as needed.) c. Find the indicated prediction interval.
(i) State the hyptheses. (ii) Sketch a scatter plot tat best represents the data. (iii) Compute the value of the correlation coefficient. Round the answer to at least three decimal places. (iv) Find the P-value. Round the answer to at least four decimal places. Test the significance of r at α=0.05. Determine whether to reject or not reject the null hypothesis.
A sample of difference scores from a repeated-measures experiment has a mean of MD = 5 with a variance of s 2 = 64. If the sample size is n = 4, what is the correct decision if using a two-tailed test with alpha = .05? A. Accept the null hypothesis, there is a significant mean difference. B. Accept the null hypothesis, there is not a significant mean difference. C. Reject the null hypothesis, there is a significant mean difference. D. Reject the null hypothesis, there is not a significant mean difference.
Consider a regression analysis with n= 51 and four potential independent variables. Suppose that one of the independent variables has a correlation of 0.49 with the dependent variable. Does this imply that this independent variable will have a very small Student's t statistic in the regression analysis with all four predictor variables? Choose all that apply. A. The correlation between the independent variable and the dependent variable could result in a very small Student's t statistic as the correlation creates a high variance. B. Correlation between the independent variable and the dependent variable is not necessarily evidence of a small Student's t statistic. C. A high correlation among the independent variables could result in a very small Student's t statistic as the correlation increases the coefficient standard errors. D. Correlation between the independent variable and the dependent variable is evidence of a small Student's t statistic.
5.
Test the null hypothesis that the slope is zero versus the two-sided alternative in the following setting using the alpha = 0.05 significance level: n = 30, yhat = 30.8 + 2.1x, and SEb1 = 1.05.
The value obtained for the test statistic, z, in a one-mean z-test is given. Also given is whether the test is two tailed, left tailed, or right tailed. Also is given the P-value.A left-tailed test: z = -1.17 P-value: 0.1210 Use technology to create a scatter plot of the data from the previous question. Include the regression line. (Hand drawn graphs will not be accepted.) The explanatory (input) variable and the response (output) variable must be clearly labeled, within the context of this problem.

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Consider the following regression results: ŷ = 4.5 -2.8x1 + 1.2*2 + 1.13, (1.8) (7) (1.2) (1.5) = 19, R² = .55. n = The minimum significance level that we can reject the null hypothesis that ₁ = -2 (two-tailed test) is at the 1% significance level. 5% significance level.