Consider the following recursive method in Java that determines if a string is a palindrome (i.e., reads the same forward or backwards) or not: Public boolean isPalindrome ( String str ){ If( str.length() ≤ 1 ) return true; else return ( str.charAt (0) == str.charAt( str.length() – 1 ) && isPalindrome( str.substring(1..str.length() - 1))); } // end of isPalindrome a. Explain convincingly why the recurrence below for f(n), where n is the length of the string parameter str, is a correct expression for the number of primitive operations required by a call isPalindrome. t(0) = Θ(1) t(1) = Θ(1) t(?) = t(? − 2) + Θ(1) b. Show that t(n) = Θ(n), solves the recurrence for t(n) in (a) above.

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