Consider the following recursive algorithm, where // denotes integer division: 3//2 = 1, 5//2 = 2, etc. F(n): if n <= 1:     return F(n//2) for i from 0 to n     for j from 0 to n//2         print(i+j)    Let function T(n) denote the running time of this algorithm. Derive T(n) and prove its worst case time complexity

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A: T(n)=T(n-1)+O(n)

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A: The Answer is

Q: number of operations

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A:

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A: SUMMARY: - Hence, we discussed all the points.

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A: answer is option d :-  O( 1 )

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