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Consider the following reaction where K. = 1.20x102 at 500 K: PCI5 (g) PCI3 (g) + Cl2 (g) A reaction mixture was found to contain 0.112 moles of PCI5 (g), 2.42x10-2 moles of PCI3 (g), and 4.24×102 moles of Cl2 (g), in a 1.00 liter containe

Consider the following reaction where K. = 1.20x102 at 500 K: PCI5 (g) PCI3 (g) + Cl2 (g) A reaction mixture was found to contain 0.112 moles of PCI5 (g), 2.42x10-2 moles of PCI3 (g), and 4.24×102 moles of Cl2 (g), in a 1.00 liter containe

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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identify the true statements in the following
Consider the following reaction where K. = 1.20x10-2 at 500 K: PCI5 (g) = PCI3 (g) + Cl2 (g) A reaction mixture was found to contain 0.112 moles of PCI5 (g), 2.42x10-2 moles of PCI3 (g), and 4.24×102 moles of Cl2 (g), in a 1.00 liter containe
Transcribed Image Text:Consider the following reaction where K. = 1.20x10-2 at 500 K: PCI5 (g) = PCI3 (g) + Cl2 (g) A reaction mixture was found to contain 0.112 moles of PCI5 (g), 2.42x10-2 moles of PCI3 (g), and 4.24×102 moles of Cl2 (g), in a 1.00 liter containe
In order to reach equilibrium Ke must increase. In order to reach equilibrium PCI3 must be produced. Qc is greater than Ke. The reaction is at equilibrium. No further reaction will occur.
Transcribed Image Text:In order to reach equilibrium Ke must increase. In order to reach equilibrium PCI3 must be produced. Qc is greater than Ke. The reaction is at equilibrium. No further reaction will occur.
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