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Consider the following reaction: PCI5(g) =PC13(g) + Cl₂(g) If 1.16x10-³ moles of PCI5, 0.216 moles of PCI3, and 0.347 moles of Cl₂ are at equilibrium in a 14.0 L container at 712 K, the value of the equilibrium constant, Kp, is

Consider the following reaction: PCI5(g) =PC13(g) + Cl₂(g) If 1.16x10-³ moles of PCI5, 0.216 moles of PCI3, and 0.347 moles of Cl₂ are at equilibrium in a 14.0 L container at 712 K, the value of the equilibrium constant, Kp, is

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider the following reaction: PC15(g) PCI3(g) + Cl₂(g) If 1.16x10-³ moles of PCI5, 0.216 moles of PCI3, and 0.347 moles of Cl₂ are at equilibrium in a 14.0 L container at 712 K, the value of the equilibrium constant, Kp, is
Transcribed Image Text:Consider the following reaction: PC15(g) PCI3(g) + Cl₂(g) If 1.16x10-³ moles of PCI5, 0.216 moles of PCI3, and 0.347 moles of Cl₂ are at equilibrium in a 14.0 L container at 712 K, the value of the equilibrium constant, Kp, is
Expert Solution
Step 1: Defining molar concentration

Answer:

Molar concentration of any specie is always equal to the ratio of its number of moles and its volume, therefore,

left square bracket PCl subscript 5 right square bracket equals straight n subscript PCl subscript 5 end subscript over straight V equals fraction numerator 1.16 cross times 10 to the power of negative 3 end exponent over denominator 14.0 end fraction straight M left square bracket PCl subscript 3 right square bracket equals straight n subscript PCl subscript 3 end subscript over straight V equals fraction numerator 0.216 over denominator 14.0 end fraction straight M left square bracket Cl subscript 2 right square bracket equals straight n subscript Cl subscript 2 end subscript over straight V equals fraction numerator 0.347 over denominator 14.0 end fraction straight M

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