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Consider the following reaction: P406(s) P4(s) + 302(g) What mass of P4 will be produced from 12.0 g of po? (Molar massses: P406 = 219.9 g/mol, P4 = 123.9 g/mol) 6.768 21.3 g 0.563 g 1.77 g Consider the reaction below: BaCl2 + Na2SO4 - BaSO4 + 2 NaCl (balanced) What is the theoretical yield of barium sulfate, BaSO4, that can be produced by the reaction of 2.84 g of Na2SO4 with 5.00 g of BaCl2? molar mass of BaCl2 = 208.33 g/mol. molar mass of BaSO4 233.38 g/mol, = molar mass of Na2SO4 = 142.04 g/mol. molar mass of NaCl = 58.44 g/mol 2.38 g 4.67 g 5.60 g 1.73 g

Consider the following reaction: P406(s) P4(s) + 302(g) What mass of P4 will be produced from 12.0 g of po? (Molar massses: P406 = 219.9 g/mol, P4 = 123.9 g/mol) 6.768 21.3 g 0.563 g 1.77 g Consider the reaction below: BaCl2 + Na2SO4 - BaSO4 + 2 NaCl (balanced) What is the theoretical yield of barium sulfate, BaSO4, that can be produced by the reaction of 2.84 g of Na2SO4 with 5.00 g of BaCl2? molar mass of BaCl2 = 208.33 g/mol. molar mass of BaSO4 233.38 g/mol, = molar mass of Na2SO4 = 142.04 g/mol. molar mass of NaCl = 58.44 g/mol 2.38 g 4.67 g 5.60 g 1.73 g

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Consider the following reaction: P406(s) P4(s) + 302(g) What mass of P4 will be produced from 12.0 g of po? (Molar massses: P406 = 219.9 g/mol, P4 = 123.9 g/mol) 6.768 21.3 g 0.563 g 1.77 g Consider the reaction below: BaCl2 + Na2SO4 - BaSO4 + 2 NaCl (balanced) What is the theoretical yield of barium sulfate, BaSO4, that can be produced by the reaction of 2.84 g of Na2SO4 with 5.00 g of BaCl2? molar mass of BaCl2 = 208.33 g/mol. molar mass of BaSO4 233.38 g/mol, = molar mass of Na2SO4 = 142.04 g/mol. molar mass of NaCl = 58.44 g/mol 2.38 g 4.67 g 5.60 g 1.73 g
Transcribed Image Text:Consider the following reaction: P406(s) P4(s) + 302(g) What mass of P4 will be produced from 12.0 g of po? (Molar massses: P406 = 219.9 g/mol, P4 = 123.9 g/mol) 6.768 21.3 g 0.563 g 1.77 g Consider the reaction below: BaCl2 + Na2SO4 - BaSO4 + 2 NaCl (balanced) What is the theoretical yield of barium sulfate, BaSO4, that can be produced by the reaction of 2.84 g of Na2SO4 with 5.00 g of BaCl2? molar mass of BaCl2 = 208.33 g/mol. molar mass of BaSO4 233.38 g/mol, = molar mass of Na2SO4 = 142.04 g/mol. molar mass of NaCl = 58.44 g/mol 2.38 g 4.67 g 5.60 g 1.73 g
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