ITS A CHEMISTRY QUESTION I NEED HELP **Chemical Reaction Problem**Consider the following reaction:\[ \text{CS}_2 + 3 \, \text{O}_2 \rightarrow \text{CO}_2 + 2 \, \text{SO}_2 \]When molecules of \(\text{CS}_2\) and \(\text{O}_2\) were allowed to react, 43.0 molecules of \(\text{CO}_2\), and twice as many molecules of \(\text{SO}_2\) were formed. There were also 1.0 molecules of \(\text{CS}_2\) in excess (leftover). How many molecules of \(\text{CS}_2\) were allowed to react with \(\text{O}_2\) initially?**Options:**- 44.0 molecules- 165 molecules- 55.0 molecules- 43.0 molecules**Selected Answer:**- 165 molecules (selected option)

Carbon disulfide reacts with oxygen to form carbon dioxide and sulfur dioxide. The equation for the balanced chemical reaction is as follows: CS2 + 3O2 → CO2 + 2SO2The stoichiometry of the balanced chemical reaction states that one mole of carbon disulfide reacts with three moles of oxygen to form one mole of carbon dioxide and two moles of sulfur dioxide. The number of moles of CO2 formed is = 43.0 The number of moles of O2 initially is =?In this reaction 1.0 molecules of carbon disulfide remain in excess, hence according to the stoichiometry of the balanced chemical reaction, we can say that: 1 mole of CO2 formed by = 1 mole of CS243.0 moles of CO2 formed by = 43.0 moles of CS2 Thus total molecules of CS2 initially present is given by: total molecules of CS2 initially present is = molecules of CS2 reacted +molecules of CS2 remains in excesstotal molecules of CS2 initially present is =43.0+1.0total molecules of CS2 initially present is =44.0The correct option is as follows: 44.0 molecules