Consider the following reaction at constant P. Use the information here to determine the value of ASsurr at 298 K. Predict whether or not this reaction will be spontaneous at this temperature. N2(g) +2 O2(g) → 2 NO2(g) ΔΗ = +66.4 ΚΙ Assurr = -66.4 J/K, reaction is not spontaneous ASsurr =-223 J/K, reaction is not spontaneous ASsurr = +223 J/K, reaction is spontaneous ASsurr =+2656 kJ/K, reaction is not spontaneous ASsurr =-66.4 J/K, it is not possible to predict the spontaneity of this reaction without more information.

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Chapter1: Chemical Foundations
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Consider the following reaction at constant P. Use the information here to determine
the value of ASsurr at 298 K. Predict whether or not this reaction will be
spontaneous at this temperature.
N2(g) +2 O2(g) → 2
NO2(g)
ΔΗ = +66.4 ΚΙ
Assurr = -66.4 J/K, reaction is not spontaneous
ASsurr =-223 J/K, reaction is not spontaneous
ASsurr = +223 J/K, reaction is spontaneous
ASsurr
=+2656 kJ/K, reaction is not spontaneous
ASsurr =-66.4 J/K, it is not possible to predict the spontaneity of this reaction
without more information.
Transcribed Image Text:Consider the following reaction at constant P. Use the information here to determine the value of ASsurr at 298 K. Predict whether or not this reaction will be spontaneous at this temperature. N2(g) +2 O2(g) → 2 NO2(g) ΔΗ = +66.4 ΚΙ Assurr = -66.4 J/K, reaction is not spontaneous ASsurr =-223 J/K, reaction is not spontaneous ASsurr = +223 J/K, reaction is spontaneous ASsurr =+2656 kJ/K, reaction is not spontaneous ASsurr =-66.4 J/K, it is not possible to predict the spontaneity of this reaction without more information.
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