Consider the following problem. Find the distance traveled in 14 seconds by an object traveling at a constant velocity of 12 feet per second. Decide whether the problem can be solved using precalculus, or whether calculus is required. O The problem can be solved using precalculus. O The problem requires calculus to be solved. If the problem can be solved using precalculus, solve it. If the problem seems to require calculus, use a graphical or numerical approach to estimate the solution. ft
Consider the following problem. Find the distance traveled in 14 seconds by an object traveling at a constant velocity of 12 feet per second. Decide whether the problem can be solved using precalculus, or whether calculus is required. O The problem can be solved using precalculus. O The problem requires calculus to be solved. If the problem can be solved using precalculus, solve it. If the problem seems to require calculus, use a graphical or numerical approach to estimate the solution. ft
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Problem Statement:**
Consider the following problem:
**Question:**
Find the distance traveled in 14 seconds by an object traveling at a constant velocity of 12 feet per second.
**Instructions:**
Decide whether the problem can be solved using precalculus, or whether calculus is required.
*Options:*
1. The problem can be solved using precalculus.
2. The problem requires calculus to be solved.
**Next Steps:**
If the problem can be solved using precalculus, solve it. If the problem seems to require calculus, use a graphical or numerical approach to estimate the solution.
**Answer Box:**
\[ \boxed{\text{ \_\_ }} \text{ ft} \]
**Analysis:**
In this case, since the velocity is constant, you can use precalculus to solve for the distance traveled. The distance \(d\) can be calculated using the formula:
\[ d = v \times t \]
where:
- \( v \) is the constant velocity (12 feet per second),
- \( t \) is the time (14 seconds).
By plugging in the values:
\[ d = 12 \, \text{ft/sec} \times 14 \, \text{sec} \]
\[ d = 168 \, \text{feet} \]
Thus, the distance traveled is 168 feet.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faf85ad90-fab3-42b7-a16f-d68658bd6ca6%2F238fb753-cedf-492f-85a9-c168bd881291%2Fvki7dc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Consider the following problem:
**Question:**
Find the distance traveled in 14 seconds by an object traveling at a constant velocity of 12 feet per second.
**Instructions:**
Decide whether the problem can be solved using precalculus, or whether calculus is required.
*Options:*
1. The problem can be solved using precalculus.
2. The problem requires calculus to be solved.
**Next Steps:**
If the problem can be solved using precalculus, solve it. If the problem seems to require calculus, use a graphical or numerical approach to estimate the solution.
**Answer Box:**
\[ \boxed{\text{ \_\_ }} \text{ ft} \]
**Analysis:**
In this case, since the velocity is constant, you can use precalculus to solve for the distance traveled. The distance \(d\) can be calculated using the formula:
\[ d = v \times t \]
where:
- \( v \) is the constant velocity (12 feet per second),
- \( t \) is the time (14 seconds).
By plugging in the values:
\[ d = 12 \, \text{ft/sec} \times 14 \, \text{sec} \]
\[ d = 168 \, \text{feet} \]
Thus, the distance traveled is 168 feet.
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