Consider the following pdf: fr (X) = = 0.06X+0.05 X = 0, 1.5, 2, 4, 5 Since it is a discrete pdf, calculations will accomplished through summation. If I were to find the cdf Fx(x) and evaluate it at x = 1.5, what would be the result?
Consider the following pdf: fr (X) = = 0.06X+0.05 X = 0, 1.5, 2, 4, 5 Since it is a discrete pdf, calculations will accomplished through summation. If I were to find the cdf Fx(x) and evaluate it at x = 1.5, what would be the result?
Consider the following pdf: fr (X) = = 0.06X+0.05 X = 0, 1.5, 2, 4, 5 Since it is a discrete pdf, calculations will accomplished through summation. If I were to find the cdf Fx(x) and evaluate it at x = 1.5, what would be the result?
Since it is a discrete pdf, calculations will accomplished through summation.
If I were to find the cdf FX(x) and evaluate it at x = 1.5, what would be the result?
Transcribed Image Text:Consider the following pdf:
\( f_X(x) = 0.06x + 0.05 \) for \( x = 0, 1.5, 2, 4, 5 \)
Since it is a discrete pdf, calculations will be accomplished through summation.
If I were to find the cdf \( F_X(x) \) and evaluate it at \( x = 1.5 \), what would be the result?
Definition Definition Probability of occurrence of a continuous random variable within a specified range. When the value of a random variable, Y, is evaluated at a point Y=y, then the probability distribution function gives the probability that Y will take a value less than or equal to y. The probability distribution function formula for random Variable Y following the normal distribution is: F(y) = P (Y ≤ y) The value of probability distribution function for random variable lies between 0 and 1.
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