Consider the following linked list and pointer called temp: →G▬B▬RE;CCE 2 3 6 H temp 10 We then perform the following operations: 1. Create a variable called x, and assign it the value obtained from dereferencing temp 2. Update temp to point at next node 3. Multiply x by 4 What is the final value of x?

Consider the following linked list and pointer called temp: →G▬B▬RE;CCE 2 3 6 H temp 10 We then perform the following operations: 1. Create a variable called x, and assign it the value obtained from dereferencing temp 2. Update temp to point at next node 3. Multiply x by 4 What is the final value of x?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Please give a detailed answer to all of the questions below.
A. A single linked list provides pointers to the next node in the sequence. Consider the below structure of the linked list and answer the questions that follow: list_head- list_tail- Assuming the front is the 1st node and the back is the Nth node, state and explain the running times for the below: i. Find a node from the front. ii. Find a node from the back. iii. Insert a node at the front. iv. Insert a node at the back. V. Erase a node from the front. vi. Erase a node from the back.
choose the correct answer
Consider a Single Linked List (SLL) of nodes, where 'node' is a type with two fields: integer data and the node type reference 'next' that refers to the next node in the list. For each part given below consider the SLL and the code given in the second column. Following the execution of the code, show the resulting list (in the answer box, for each part, use the arrow key to draw the list as: head-----> ? -------> ? -------> ?). List and Java Code | head →1-2-3→4→ null node ptr=head; node newnode = new node(0); // data=0 head = newnode; newnode.next=ptr; b head 1→2→3→4→ null node ptr=head; node newnode = new node(6); // data=6 while(ptr.next!=null) { ptr=ptr.next; } ptr.next=newode; head -1-2- 3→ 4→ mull node ptr=head; ptr=ptr.next; head=ptr;
Please written by computer source 16 In this lab, you need to implement a simple linked list using dynamic memory allocation. The structure of node in the linked list has been declared in “lab3.h”. Also, the functions of linked list have been declared in “lab3.h” as well. In “main.c”, these functions are called. Your work is to finish these function implementations in a separate C source file, and create a makefile which can compile your separate C source file along with “main.c” and “lab3.h”. You can follow the comments in “main.c” and “lab3.h” to finish this lab. Please do not change “main.c” and “lab3.h”, because your separate C source file will be compiled with these two files posted on BlackBoard. When you test your program, please put “main.c”, “lab3.h”, your separate C source file and your makefile in the same directory and compile. Code provided: lab3.h #include<stdio.h> #include<stdlib.h> #ifndef LAB3_H #define LAB3_H struct node { int data; struct…
This task is to develop a software for a bookshop that handles the purchases through online. When the customer places order to buy a book, the shop will search for the specific item upon
3. From an empty linked list, the following operations are performed, in order: addFirst (30), addFirst (40), addLast (60), addLast (80), insertBefore (50, 30. Draw the list that results after those operations. Draw ONLY the final result.
Given a linked stack L_S and a linked queue L_Q with equal length, what do the following procedures to do the lists? Here, TOP is the top pointer of L_S, and FRONT and REAR are the front and rear of L_Q. What are your observations regarding the functionality of the two procedures? procedure procedure WHAT_IS_COOKING1 (TOP, FRONT, WHAT_IS_COOKING2 (TOP, FRONT, REAR) REAR) /* TEMP3 TEMP, TEMP1, TEMP2 and/* TEMP, TEMP1, temporary TEMP3 are variables*/ TEMP1 = FRONT; TEMP2 TOP; while (TEMP1# Nil AND TEMP2 Nil) do TEMP3 = DATA (FRONT); DATA (FRONT) = DATA (TOP); DATA (TOP) = TEMP3; TEMP1 = LINK (TEMP1); PREVIOUS = TEMP2; TEMP2 = LINK (TEMP2); endwhile TEMP = TOP; TOP = FRONT; FRONT TEMP; REAR PREVIOUS; end WHAT IS COOKING 1 are variables*/ TEMP2 and temporary TEMP = TOP; while (LINK (TEMP) # Nil) do TEMP = LINK (TEMP); endwhile TEMP1= TOP; REAR = TEMP; TOP = FRONT ; FRONT = TEMP1; end WHAT_IS_COOKING2
Develop a procedure that will allow you to remove from a linked list all of the nodes that share a key?
To check if the linked list is circular, we need Select one: a. A pointer temp that passes it to the last node and it must the same value as the first one b. A pointer temp that passes it through all nodes an checks the next of each node is equal to head c. A pointer temp that passes it through all nodes and checks the next of each node is equal to NULL d. A pointer temp that passes it through all nodes and checks if all data are the same
The following step is used to remove first node from the AVAIL list. NEW: =AVAIL AND AVAIL: =LINK[AVAIL] Select one: True False
Write a Java Program to do the following: Create a LinkedList object and store 5 different Double objects Using a Listlterator do the following: a. Print all data stored in LinkedList object in FORWARD and BACKWARD direction.