Consider the following intuition for a sorting algorithm. Let A be a list of real numbers. If A is of size 0 or 1, return it since it is already sorted. Otherwise, pick the last element of A to be used as a pivot and call it p. For each element e of A except the last element, if e ≤p, place e in a list called L. On the other hand, if e > p, place e in a another list called R. Repeat this procedure on L and R and call the resulting lists L' and R'. Make a new list by adding p between L' and R'. Return the result.
Consider the following intuition for a sorting algorithm. Let A be a list of real numbers. If A is of size 0 or 1, return it since it is already sorted. Otherwise, pick the last element of A to be used as a pivot and call it p. For each element e of A except the last element, if e ≤p, place e in a list called L. On the other hand, if e > p, place e in a another list called R. Repeat this procedure on L and R and call the resulting lists L' and R'. Make a new list by adding p between L' and R'. Return the result.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Questions: PLease answer all and for 2a write pseudocode not explanantion.
(a) Write pseudocode following the above intuition.
(b) Determine the worst-case asymptotic run time of this
(c) Assume that the sizes of L and R are equal at each step of the algorithm. Find a recurrence relation describing the run time in this case.
(d) Given this recurrence relation, what is the asymptotic run time of the algorithm? Be sure to justify your answer using the master theorem.
Transcribed Image Text:Consider the following intuition for a sorting algorithm. Let A be a list of real numbers. If A is
of size 0 or 1, return it since it is already sorted. Otherwise, pick the last element of A to be used
as a pivot and call it p. For each element e of A except the last element, if e ≤p, place e in a list
called L. On the other hand, if e > p, place e in a another list called R. Repeat this procedure
on L and R and call the resulting lists L' and R'. Make a new list by adding p between L' and
R'. Return the result.
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