Consider the following integral. Sketch its region of integration in the xy-plane. [.², (a) Which graph shows the region of integration in the xy-plane? ? (b) Write the integral with the order of integration reversed: Tº. 36 A = B = C = D= Jy² with limits of integration y sin (x²) dx dy y sin (2²) da dy = (c) Evaluate the integral. D - y sin (2²) dy dz JC A (Click on a graph to enlarge it) 6 B D

Q: Is g = {(x, y) ∈ [−5, 5] × R : x^2 + y^2 = 25} a function from [−5, 5] to R.

A:

Q: Find the exact area of the region that lies beneath the curve y = 2 sin(x), 0 < x < n.

A:

Q: Find the area of the region in the 1 quadrant bounded by y = x2 + 1, y = 1 – x², and x = 1.

A: The given equations of the curve are y=x2+1, y=1-x2 and x=1. Compute the area bounded by the above…

Q: x dy - y dx

A:

Q: Find the areas enclosed by the following curves: (a) y = x² – 2 and y = 2 -

A: The area enclosed between the given curve will be the shaded portion as shown in the below diagram

Q: Find : ( 39 - Sincm) dx +(2x*) dy when C is the boundary of the limited area by curvess y= e* and in…

A: Given that I=∫c3y-sin x dx+2x2 dy                                   ……(1)   Boundary is given as…

Q: Find w, where w3 = 1 + i. i? = -1.

A:

Q: sin(z)

A:

Q: 2. Let D be the parallelogram bounded by the lines x+3y = 5, –x + y = 3, –x + y = 2, and x + 3y = 0.…

A: Let us consider the integral I=∫∫Df(x,y) dydx where D is the region in xy-coordinate  To make the…

Q: 16. Find (1) the net area and (ii) the area of the region above the x-axis bounded by y=121-x².…

A:

Q: d the area of the region bounded by the curves: y = cos(nx) and y = -1 + 4x²

A:

Q: dy evaluate dx (sinx+1) y = (cosx+1)'

A: Given,          y=sinx+1cosx+1

Q: Find the area bounded by the curve y? 4x and the lines x=1 and x=4.

A: Area bounded by a curve y=f(x) and the lines x=a and x=b is given by, A=∫abf(x)dx  We know, ∫xndx=…

Q: iate by contour integrat:

A: ∫0∞ dx1+x2

Q: The population of a community is known to increase at a rate proportional to the number of people…

A: