Consider the following integral equation, so called because the unknown dependent variable, y, appears within an integral: sin(5(t – w)) y(w) dw 2t?. This equation is defined for t > 0. a. Use convolution and Laplace transforms to find the Laplace transform of the solution. Y(s) = L{y(t)} = ((s^2)+25)/(s^3) b. Obtain the solution y(t). y(t) = %3D

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Consider the following integral equation, so called because the unknown dependent variable, y, appears within an integral:
| sin(5(t – w)) y(w) dw =
2t2.
This equation is defined for t > 0.
a. Use convolution and Laplace transforms to find the Laplace transform of the solution.
Y(s) = L{y(t)} = ((s^2)+25)/(s^3)
b. Obtain the solution y(t).
y(t) =
Transcribed Image Text:Consider the following integral equation, so called because the unknown dependent variable, y, appears within an integral: | sin(5(t – w)) y(w) dw = 2t2. This equation is defined for t > 0. a. Use convolution and Laplace transforms to find the Laplace transform of the solution. Y(s) = L{y(t)} = ((s^2)+25)/(s^3) b. Obtain the solution y(t). y(t) =
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