Consider the following initial-value problem. y" - 3y' = 8e²t - 2e-t, y(0) = 1, y'(0) = −1 Find L{f(t)}, for f(t) = 8e²t - 2e-t. (Write your answer as a function of s.) 6s + 12 L(f(t)) = (s-2) (s+1) Use the Laplace transform to solve the given initial-value problem. y(t) = 8e²t - 2e

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A: NOTE: Refresh your page if you can't see any equations. . here we have

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