Consider the following initial-value problem. Find L{f(t)}, for f(t) = L(f(t)) : y" − 3y' = 4e²t — 2e¯t, y(0) = 1, y'(0) = −1 - = 4e²t 2e-t. (Write your answer as a function of s.) Use the Laplace transform to solve the given initial-value problem. y(t) =

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