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Consider the following indefinite integral. The integrand decomposes into the form: Compute the coefficients: a = 6 b = 3 c = 7x^2 +27 d = 7x^2-27 6x³ + 3x² x² ax+b+ x с 47x - 18 9 3 Now integrate term by term to evaluate the integral. Answer: (7*In(abs(x^2-9))-3*In(abs(x+3))+3*In(abs(x-3)))/2+3*x^2+3*x + dr d x + 3 + C

Consider the following indefinite integral. The integrand decomposes into the form: Compute the coefficients: a = 6 b = 3 c = 7x^2 +27 d = 7x^2-27 6x³ + 3x² x² ax+b+ x с 47x - 18 9 3 Now integrate term by term to evaluate the integral. Answer: (7*In(abs(x^2-9))-3*In(abs(x+3))+3*In(abs(x-3)))/2+3*x^2+3*x + dr d x + 3 + C

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I just can't get c and d right even every other ones are correct. How can you seperate (7x+9)/(x^2 - 9)

Consider the following indefinite integral. The integrand decomposes into the form: Compute the coefficients: a = 6 b = 3 c = 7x^2 +27 d = 7x^2-27 6x³ + 3x² x² ax+b+ x с 47x - 18 9 dx d + 3 x + 3 Now integrate term by term to evaluate the integral. Answer: (7*In(abs(x^2-9))-3*In(abs(x+3))+3*In(abs(x-3)))/2+3*x^2+3*x + C
Transcribed Image Text:Consider the following indefinite integral. The integrand decomposes into the form: Compute the coefficients: a = 6 b = 3 c = 7x^2 +27 d = 7x^2-27 6x³ + 3x² x² ax+b+ x с 47x - 18 9 dx d + 3 x + 3 Now integrate term by term to evaluate the integral. Answer: (7*In(abs(x^2-9))-3*In(abs(x+3))+3*In(abs(x-3)))/2+3*x^2+3*x + C
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