Consider the following hypothesis test: He: µ =18 A sample of 48 provided a sample mean = 17 and a sample standard deviation s = 4.8. Enter negative values as negative numbers. H.: µ # 18 a. Compute the value of the test statistic (to three decimal places). -1.443 O b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value (to two decimal places). p-value is between 0.10 and 0.16 8 C. At a = 0.05, what is your conclusion? p-value is greater than 0.05, do not reject Ho. d. What is the rejection rule using the critical value? Reject Ho if t is equal to 2.012 or t is greater than or equal to 2.012 v What is your condlusion (to three decimal places)? t = -1.443 do not reject Ho.

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Consider the following hypothesis test:

\[
H_0: \mu = 18 \\
H_a: \mu \neq 18
\]

A sample of 48 provided a sample mean \(\bar{x} = 17\) and a sample standard deviation \(s = 4.8\). Enter negative values as negative numbers.

a. Compute the value of the test statistic (to three decimal places).

\[ t = -1.443 \] ✓

b. Use the \(t\) distribution table (Table 2 in Appendix B) to compute a range for the \(p\)-value (to two decimal places).

\(p\)-value is between \([0.10 , 0.16]\) ✗

c. At \(\alpha = 0.05\), what is your conclusion?

\(p\)-value is \(\text{greater than 0.05, do not reject } H_0\). ✓

d. What is the rejection rule using the critical value?

Reject \(H_0\) if \(t \text{ is } \text{equal to 2.012} \text{ or } t \text{ is } \text{greater than or equal to 2.012}\) ✓ 

What is your conclusion (to three decimal places)?

\[ t = -1.443 \] ✓ do not reject \(H_0\).
Transcribed Image Text:Consider the following hypothesis test: \[ H_0: \mu = 18 \\ H_a: \mu \neq 18 \] A sample of 48 provided a sample mean \(\bar{x} = 17\) and a sample standard deviation \(s = 4.8\). Enter negative values as negative numbers. a. Compute the value of the test statistic (to three decimal places). \[ t = -1.443 \] ✓ b. Use the \(t\) distribution table (Table 2 in Appendix B) to compute a range for the \(p\)-value (to two decimal places). \(p\)-value is between \([0.10 , 0.16]\) ✗ c. At \(\alpha = 0.05\), what is your conclusion? \(p\)-value is \(\text{greater than 0.05, do not reject } H_0\). ✓ d. What is the rejection rule using the critical value? Reject \(H_0\) if \(t \text{ is } \text{equal to 2.012} \text{ or } t \text{ is } \text{greater than or equal to 2.012}\) ✓ What is your conclusion (to three decimal places)? \[ t = -1.443 \] ✓ do not reject \(H_0\).
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