Consider the following hydroboration/oxidation of an alkene. OH 1. BH3, THF -CH3 2. HаОг, NaOH, H-О "CH3 The intermediate formed in the first step of this reaction is: H2B OH BH2 H H B OH BH2 BH2 .CH3 "CH3 "CH3 "CH3 ""CH3 D E A в
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![Consider the following hydroboration/oxidation of an alkene.
OH
1. BH3, THF
-CH3
2. HаОг, NaOH, H-О
"CH3
The intermediate formed in the first step of this reaction is:
H2B
OH
BH2
H H
B
OH
BH2
BH2
.CH3
"CH3
"CH3
"CH3
""CH3
D
E
A
в](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F114ae6ac-c817-4c1c-b46e-eb7668ccf25f%2Fd5282c4b-60f8-48e9-b14e-1b3f55f2db33%2Fnvnlke_processed.png&w=3840&q=75)
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