10) Solve all parts of the question correctly, please. Consider the following four data sets in the table below. Complete parts (a) through (g) below.Click the icon to view the four data sets.Data setsa. Compute the mean of each data set.x (Data Set I)x (Data Set II)Data Set IData Set IIData Set IIData Set IV%3D=119.2x (Data Set III)x (Data Set IV)2619368.1936.(Type integers or decimals. Do not round.)9.19.3849.110b. Although the four data sets have the same means, in what respect are they quite different?O A. Each data set has a unique median.O B. The amount of variation within each data set differs among the data sets.PrintDoneO C. The amount of variation within each data set is the same among the data sets, but with different values.D. The data sets are not different as the four data sets are identical. c. Which data set appears to have the least variation? the greatest variation?Data setV appears to have the least variation. Data setV appears to have the greatest variation.d. Compute the range of each data set.Range (Set I)Range (Set II)Range (Set III)Range (Set IV)(Type integers or decimals. Do not round.)e. Use the defining formula to compute the sample standard deviation of each data set.s (Set I)s (Set II)%3Ds (Set III)s (Set IV)(Type integers or decimals. Round to one decimal place as needed.)f. From your answers to parts (d) and (e), which measure of variation better distinguishes the spread in the four data sets: the range or the standard deviation? Explain your answer.O A. The range distinguishes spread better because it shows that having different standard deviations doesn't imply that the means must be different.O B. The standard deviation distinguishes spread better because it is resistant to outliers, and is therefore more robust than the range.OC. The range distinguishes spread better because it shows that the sets are structurally similar, because their extrema are equally spread out.O D. The standard deviation distinguishes spread better because it shows that the sets are structurally different, despite having similar ranges and means.

Answered: Image /qna-images/answer/f10468a5-d753-49ed-911c-3a5da745a291.jpg(b). In each data set the number of observations are 10 Median is the average of 5th and 6th terms. Median(Set I) = 4+52 = 4.5 Median(Set II) = 1+92 =5 Median(Set III) = 5+52 = 5 Median(Set IV) = 4+52 = 4.5 The data sets do not have same median. The data sets have different values. Therefore, they are not identical. The variation is not same since one set has constant data and one set has more variation variation among the observations. Hence amount of variation within each dataset differs among the data sets. (c). The dataset III has constant values implies it has no variation. The data set II has only two different values 1 and 9 has more variation among the values. Hence set III appears to have least variation and set II appears to have greatest variation. (f). From (d) the range of set I, set II, set IV are same. From (e) the standard deviation of set I, set II, set IV are different. Therefore, we conclude that the standard deviation distinguishes spread better because it shows that the sets are structurally different despite having similar ranges and means. The answer is option D.