Consider the following flow network. S-V₁-V3 5-V2->V4->E 5-7√2-2V1-V3- G S->V₂V₁ →V₁ ts (12 6,6 V1 10,1 V2 7,7 6,0 3,3 V3 5,2 V4 8,5 5,5 a) Vertex | Flow in V₁ 611 Vz V₂ 2+3 Flow out ㅋ 3+1 5+2 5 (a) Check it is a proper flow, by confirming that the flow out of each internal vertex (v₁, ..., V4) equals the flow in. (b) Find an augmenting path →√√₂ → √n → Va >> Vz ⇒ t 3 State which edges, on your path, have minimum and maximum flow-capacity. (d) Augment the flow. (e) Run the algorithm one more time to find the min-cut, and check that the flow across the cut equals the capacity. capacity of flow is 15 (12+3)
Consider the following flow network. S-V₁-V3 5-V2->V4->E 5-7√2-2V1-V3- G S->V₂V₁ →V₁ ts (12 6,6 V1 10,1 V2 7,7 6,0 3,3 V3 5,2 V4 8,5 5,5 a) Vertex | Flow in V₁ 611 Vz V₂ 2+3 Flow out ㅋ 3+1 5+2 5 (a) Check it is a proper flow, by confirming that the flow out of each internal vertex (v₁, ..., V4) equals the flow in. (b) Find an augmenting path →√√₂ → √n → Va >> Vz ⇒ t 3 State which edges, on your path, have minimum and maximum flow-capacity. (d) Augment the flow. (e) Run the algorithm one more time to find the min-cut, and check that the flow across the cut equals the capacity. capacity of flow is 15 (12+3)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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struggeling to do part c)
Part c only
![Consider the following flow network.
S-V₁-V3 - S-V₂V/₁ →V₂ts
5-V2-> V4-E
5-22-21-03-2
=
6,6
V1
10,1
V2
7,7
6,0
3,3
V3
5,2
V4
8,5
5,5
a)
Vertex Flow in
V^
611
Vz
V3
V4
2+3
Flow out
3+1
5+2
5
(a) Check it is a proper flow, by confirming that the flow out of each internal vertex (v₁, ..., v4)
equals the flow in.
(b) Find an augmenting path: SV₂V₁ → Va → V3 → t (3)
c) State which edges, on your path, have minimum and maximum flow-capacity.
(d) Augment the flow.
(e) Run the algorithm one more time to find the min-cut, and check that the flow across the
cut equals the capacity. capacity of flow is 15 (12+3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff236ec6d-59e1-428f-8115-1fdcab9d5ceb%2F6f256c93-c599-4f54-9f5a-8b0c35fdb47d%2F3yzxgna_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the following flow network.
S-V₁-V3 - S-V₂V/₁ →V₂ts
5-V2-> V4-E
5-22-21-03-2
=
6,6
V1
10,1
V2
7,7
6,0
3,3
V3
5,2
V4
8,5
5,5
a)
Vertex Flow in
V^
611
Vz
V3
V4
2+3
Flow out
3+1
5+2
5
(a) Check it is a proper flow, by confirming that the flow out of each internal vertex (v₁, ..., v4)
equals the flow in.
(b) Find an augmenting path: SV₂V₁ → Va → V3 → t (3)
c) State which edges, on your path, have minimum and maximum flow-capacity.
(d) Augment the flow.
(e) Run the algorithm one more time to find the min-cut, and check that the flow across the
cut equals the capacity. capacity of flow is 15 (12+3)
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