Consider the following expression for the equilibrium constant that represents the dissociation of iodic acid into hydronium and iodate ions. = 0.161 [H3O+] [103] Ka = [HIO3] When 176 g of iodic acid is dissolved in water to give an aqueous solution with a final volume of 1.00 L. Calculate the % dissociation of iodic acid to form iodate anions. The molar mass of iodic acid is 175.91 g mol-¹. a. 0.161% b. 16.1% OC. 32.8% O d. 40.1% Oe. 83.9%
Consider the following expression for the equilibrium constant that represents the dissociation of iodic acid into hydronium and iodate ions. = 0.161 [H3O+] [103] Ka = [HIO3] When 176 g of iodic acid is dissolved in water to give an aqueous solution with a final volume of 1.00 L. Calculate the % dissociation of iodic acid to form iodate anions. The molar mass of iodic acid is 175.91 g mol-¹. a. 0.161% b. 16.1% OC. 32.8% O d. 40.1% Oe. 83.9%
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![Consider the following expression for the equilibrium constant that represents the dissociation of iodic acid into hydronium and iodate ions.
Ka
[H3O+] [103]
[HIO3]
=
= 0.161
When 176 g of iodic acid is dissolved in water to give an aqueous solution with a final volume of 1.00 L. Calculate the % dissociation of iodic acid to form iodate
anions. The molar mass of iodic acid is 175.91 g mol-¹.
a. 0.161%
b.16.1%
OC. 32.8%
Od. 40.1%
e. 83.9%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5f1d33a-b082-4c92-a24c-790bf2c10953%2F0d4e189f-8ea5-498f-b2f4-51823bb9c1f3%2F6aezvk6_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the following expression for the equilibrium constant that represents the dissociation of iodic acid into hydronium and iodate ions.
Ka
[H3O+] [103]
[HIO3]
=
= 0.161
When 176 g of iodic acid is dissolved in water to give an aqueous solution with a final volume of 1.00 L. Calculate the % dissociation of iodic acid to form iodate
anions. The molar mass of iodic acid is 175.91 g mol-¹.
a. 0.161%
b.16.1%
OC. 32.8%
Od. 40.1%
e. 83.9%
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