**Equilibrium Analysis in a Chemical Reaction****Consider the following equilibrium:**\[ \text{Cu}^{2+} (aq) + 4\text{NH}_3 (aq) \rightleftharpoons \text{Cu(NH}_3\text{)}_4^{2+} (aq) \quad (K_f = 4.8 \times 10^{12}) \]A solution is made by mixing 15.0 mL of 0.90 M CuSO₄ and 1.00 L of 0.530 M NH₃. Assume additive volumes to answer the following questions. Give all answers to three significant figures.**Questions:**a) What is the concentration of NH₃ in the resulting solution?\[ [\text{NH}_3] = 0.47 \, \text{M} \, \text{✔} \]b) What is the concentration of \(\text{Cu(NH}_3\text{)}_4^{2+}\) in the resulting solution?\[ [\text{Cu(NH}_3\text{)}_4^{2+}] = 5.3 \times 10^{-2} \, \text{M} \, \text{✘} \]c) What is the concentration of \(\text{Cu}^{2+}\) in the resulting solution?\[ [\text{Cu}^{2+}] = 5.3 \times 10^{-2} \, \text{M} \, \text{✘} \]**Explanation:**In this analysis, the equilibrium constant \( K_f \) is an indicator of the reaction's favorability towards the product side. The formation of the complex ion \(\text{Cu(NH}_3\text{)}_4^{2+}\) is highly favored given the large value of \( K_f \), meaning that the equilibrium lies far to the right. The questions explore the concentrations of ammonia, the complex ion, and copper ions remaining in the solution after equilibrium is established.The checkmarks and crosses indicate whether the computed values are correct or incorrect.

Answer:- This question is answered by using the simple concept of calculation of equilibrium…

Consider the following equilibrium: Cu²+ (aq) + 4NH3(aq) → Cu(NH3)4²+ (aq) (Kf = 4.8e+12) A solution is made by mixing 15.0 mL of 0.90 M CuSO4 and 1.00 L of 0.530 M NH3. Assume additive volumes to answer the following questions. Give all answers to three sig figs. a) What is the concentration of NH3 in the resulting solution? [NH3] = 47 M b) What is the concentration of Cu(NH3)42+ in the resulting solution? [Cu(NH3)4²+] = [5.3e-2 XM c) What is the concentration of Cu²+ in the resulting solution? [Cu2+] = 5.3e-2 X M

Consider the following equilibrium: Cu²+ (aq) + 4NH3(aq) → Cu(NH3)4²+ (aq) (Kf = 4.8e+12) A solution is made by mixing 15.0 mL of 0.90 M CuSO4 and 1.00 L of 0.530 M NH3. Assume additive volumes to answer the following questions. Give all answers to three sig figs. a) What is the concentration of NH3 in the resulting solution? [NH3] = 47 M b) What is the concentration of Cu(NH3)42+ in the resulting solution? [Cu(NH3)4²+] = [5.3e-2 XM c) What is the concentration of Cu²+ in the resulting solution? [Cu2+] = 5.3e-2 X M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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