Consider the following equation Mg(OH)2 + 2HCl à MgCl2 + 2H2O If 50.6 g of Mg(OH)2 is mixed with 45.0 g of HCl, what is the limiting reagent? How many grams of MgCl2 are produced? If 55.4 g of MgCl2is recovered, what is the percent yield?

Q: What is the percent yield for this reaction?

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Q: The theoretical yield of Mg(OH)2 when the reaction below was performed in the laboratory, was 5.45…

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A: Percentage yield: It is the ratio of actual yield to the theoretical yield multiplied by 100.

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Q: what is the percent yield?

A: Number of moles = mass/molar mass  Percent yield =(actual yield/theoretical yield) × 100%

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