Consider the following DFA M₁0: 90 0 1 q1 92 1 1 q6 1 0 94 0 0 1 Give a regular grammar that generates L(M₁0). 1 q3 0 q5

Q: Consider the following grammar G=(V, TP, S), V = (S, X), T = {0, 1} and productions P are S 0 10X11…

A: Ambiguous grammar: A grammar which makes more than one left most derivation or more than one right…

Q: Find context-free grammars for the following languages (with n 2 0, m 2 0) L={a®bm:n=m- 1).

A: Context free grammar for given L is as follows :

Q: Convert the following grammar to Chomsky Normal Form: S → T U T → x | y U → + S U | ε

A: The Answer is in step2

Q: Convert the grammar over Σ = {0} into Chomsky Normal Form: A → BAB | B | ε B → 00 | ε

A: To convert the given grammar over Σ = {0} into Chomsky Normal Form, we need to follow these steps:…

Q: Σ = {a, b}. For each of the following languages, find a grammar that generates it.

A: Grammar of given languages

Q: (a) L = {abc : 1 k = m or m ≤ k}. = u:

A: Note: As per our guidelines we are supposed to answer only one question. Kindly repost other…

Q: CT.

A: I have answered it previously.   As we know Grammar are the rules which defines the expressions.…

Q: Convert the following Context-Free Grammar (CFG) to Chomsky Normal Form (CNF) where, Σ={a, b}. [10]…

A:

Q: a,Z ->aZ |а,а ->empty a,b->a A1 |а, а->empty a,b ba S empty,Z->empty |A3 A2 Z,empty->empty а,а->аа

A: Answer: This question from Theory of computation. and here we have solved question in handwritten…

Q: Regular grammar, S ⟶⟶ aS | bS |a | bb, will generate the following language L: Group of answer…

A:

Q: The following shows a simple context free grammar (CFG) : Which of the following sentences are…

A: The question is to choose which among the following sentences is recognized by the given grammar.

Q: Give a context-free grammar that generates the following language, with alphabetΣ is {0, 1, #}:…

A: One of the following formats must correspond to the language above:

Q: Convert the following grammar to chomsky normal forms, S → aAbB A aA/ a B→ bB/b

A: The Answer is

Q: Convert the following grammar over alphabet {0,1} into Chomsky hormal form: A AD LA Q1

A: Here the non terminal A is useless since it is not terminating  After removing A, the grammar…

Q: Determine L(Go), where Go be the following grammar: S- 151 |0|E L(Go) = {1"01" | n20} U { 12" | n…

A: I have given the solution to the above question below.

Q: CYK algorithm

A: Given :- A grammar G  with productions is given as, S → AB A → AS | BS | a B → SA | b   Need to…

Q: Give a context-free grammar that generates the following language, with alphabetΣ is {0, 1, #}:…

A: According to the information given:- We have to generate the language with alphabet Σ{0,1,#}

Q: Provide a Regular Expression for the following context-free grammar: S→SS|A|B|C…

A: Given CFG,   S->SS|A|B|C   A->A011|0A11|01A1|011A|€   B->B110|1B10|11B0|110B|€…

Q: Consider the following grammar. S →0A B1 A → 08 B → 1|ɛ Which of the following set is the FIRST(S)?…

A: For the given grammar the set of first has been chosen from the given options please refer to this…

Q: expr → expr + term | term term → term * factor | factor factor → b|c|d|(expr)

A: Parse tree parse tree or the derivation tree are the rooted tree that represents the syntactic…

Q: Define an EBNF grammar for any valid number, not starting with zero, like the next examples: 1 102…

A: In this question we have to define an EBNF grammar for any valid number, not starting with zero…

Q: Find context-free grammar for the following regular expression. (a +b)*cc(a+b)*

A: GIVEN: Find context-free grammar for the following regular expression. (a +b)*cc(a+b)*

Q: b) What is the associativity of the % operator? a) left b) right c) neither c) What is the…

A: b) Associativity of the % Operator:In the grammar G:S - > T% * S | THere, the % operator is…

Q: ii. Using the grammar fragment below and the input symbols jwwkyn, demonstrate how shift-reduce…

A: Shift reduce parsing  S   jPkQn P   Pw|w Q  y

Q: The following grammar generates the language of regular expression 0*0(0 + 1)* S → A1B A → 0A | ɛ B…

A: 1. leftmost derivation is  S→A1B   →0A1B   →00A1B   →001B    →0010B   →00101B   →00101 Rightmost…

Q: Show that the following grammar is ambiguous. S → AB | C A → 11 |0 В — 22 10 С — 0С10

A: We are going to see if the given grammar is ambiguous. TIP- If more than 1 parse tree exist for same…

Q: Consider the following grammar. S → 0AB1 A → 08 B→ 1|ɛ Which of the following set is the FIRST(S)?…

A: Introduction FIRST and FOLLOW Function: We can complete the entries of a M-table by using the…

Q: The language generated by the grammar G=({S}, {a,b), S, P) with P given as: S-> as /bs/alb can be…

A: Given Grammer G=({s},{a,b},S,P) with P given asS->aS|bS|a|b

Q: Create a parse tree of the string accepted by the grammar.  Given the grammar S→ aS|aSbS|ε  a.…

A:

Q: Give context-free grammars generating each of the following languages over Σ = {0, 1}: E a) {01m0n:…

A: Context Free Grammar: A grammar contain a context free grammar then it must be a context free…

Q: Give a context-free grammar for each of the following languages: a. L1 = {a"b³mc+, n, m 2 0} , E=…

A: a. L1 CFG: S-> aaSc | B | epsilon B-> bbbBc | epsilon As we know The string can be with only…

Q: following rami S → AB1 | 0 A → 00A | B B → 1A1 GNF

A: GNF:- GNF stands for Greibach normal form. A CFG(context free grammar) is in GNF(Greibach normal…

Q: Consider the following context free grammar: S -> ABC A -> aAb | C B-> CB | d C -> eC | E Show…

A: 1.

Q: → A + B | B A+B > BX C | C → (A) | a

A: Solution - In the given question, we have to construct parse trees for the given strings.

Q: Convert grammar from the previous question to an equivalent PDA S→ ASB | A01 | A A AS A B→ 10 | E

A:

Q: Which string CANNOT be generated by the grammar

A: Solution - In the given question, we have to find the string that cannot be generated by the given…

Q: Consider the following grammar: GS $$ SAM M ->> SE A a Eb A A ->> E a Bb Ale B - b E | a B B (a)…

A: Parse tree is also called as derivation tree or concrete syntax tree which is an ordered, rooted…