Consider the following curve. x = sin(6t), y = -cos(6t), z = 24t Using the given parametric equations, give the corresponding vector equation r(t). r(t) = (sin (6t), - cos (6t),241) Find r'(t) and Ir'(t)\. r'(t) = |r'(t) = √612 (6 cos (61),6 sin (6t),24) Find the equation of the normal plane of the given curve at the point (0, 1, 4x). -6x+12z-48=0 x Now consider the osculating plane of the given curve at the point (0, 1, 4x). Determine each of the following. T(t) = T'(t) IT'() = N(t) = -sin (61)j + cos(61)k x Find the equation of the osculating plane of the given curve at the point (0, 1, 4x). X
Consider the following curve. x = sin(6t), y = -cos(6t), z = 24t Using the given parametric equations, give the corresponding vector equation r(t). r(t) = (sin (6t), - cos (6t),241) Find r'(t) and Ir'(t)\. r'(t) = |r'(t) = √612 (6 cos (61),6 sin (6t),24) Find the equation of the normal plane of the given curve at the point (0, 1, 4x). -6x+12z-48=0 x Now consider the osculating plane of the given curve at the point (0, 1, 4x). Determine each of the following. T(t) = T'(t) IT'() = N(t) = -sin (61)j + cos(61)k x Find the equation of the osculating plane of the given curve at the point (0, 1, 4x). X
Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter8: Polar Coordinates And Parametric Equations
Section8.CT: Chapter Test
Problem 8CT
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