Consider the following converter topology in a battery charger application. Vs= Vbatt = 240V Vs • L=10mH . R = 50 • Switching frequency = 2kHz Vs=333V Assume ideal switching elements with no losses and state/determine: 4. the maximum value of the ripple current 5. the minimum value of the ripple current 6. peak to peak ripple current Use Duty Cycle of 50% [TUT] Vout inh load Vbatt

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Q: QUESTION 10 The lowest address belod in the P OM ie

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Q: Problem 1 Rp Vt = 1.2 V K = 0.02 mA/V² Voo VDD = 8 V Rp =2K

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Q: Determine I

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Q: 40 ww 200 40 4V SV 202 0.04 A -0.04 A 0,1 A -4V wW-

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Q: 16 v₁² =√₁² + 2ax = 0 + 2* 7.9*10⁰*0.05 vo 4₁ = (v₁²0.0 ans = 8.89*107

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Q: 3 S+6 2. 25+65+4

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Power Measurement

According to Blondel's theorem, the total power is measured with one less number of wattmeters than the number of wires present in the system. So, a single-phase and two-wire system will require one wattmeter and a single-phase and the three-wire system will require two wattmeters, and a three-phase and the three-wire system will also require two wattmeters and a three-phase and the four-wire system will require three wattmeter devices. The wattmeter is a device that measures power using one voltage and one current input as shown in the above figure. Multiple current or voltage input pair cables are used by many power analyzers and digital storage oscilloscopes (DSOs) for measuring watts, in effect within a single instrument acting as multiple wattmeters. It is possible to measure three-phase and four-wire power with one correctly specified power analyzer.