I want solution with step Lab 3 - Selection Control Statements (Part 2)3.0. Lab GoalsSolve problems using if, if/else, and nested if and if..else.Solve problems using switch; multiple-selection statement• Use of equality and relational operatorsUse of logical operators3.1. Exercise 1Consider the following code fragments.if (x != 0 && y % x == 0)System.out.printf("%d multiple of %d\n", y, x);if (x > 0 || y++ > x)System.out.printf("%d is also positive\n", y);Answer the following questions:1) What is the output when x = 5 and y = 252) What is the output when x = 0 and y = 63) What is the output when x = -2 and y = -84) What is the output when x = 0 and y = 05) If we inverse the two conditions of the first if statement:if ( y % x == 0 && x != 0))It will result the same output when x = 0 and y= 6?6) Explain why if the first condition of the second if statement is true, y is notincremented3.2. Exercise 2Using the switch statement, rewrite the solution of the exercise 6 from the previous lab(Lab 2).

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Answered: Consider the following code fragments.…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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It is an algorithm problem.
need help with part b, they are incorrect
Solve the recurrence relation by substitution: T(n) = T(n-1) + 2^n
Let ap = 1, an = an-1 + 3 be the recurrence relation of algorithm A and T(1) = 1, T(n) = T(n/5)+n be the recurrence relation of algorithm B. 1. Find the solution for both relations. Use any method.
Please explain your answer for both questions. For the first part n is greater than or equal to zero
Correct answer will be upvoted else downvoted. Computer science. You don't care to alter your bearing excessively, so you will make close to n−1 heading changes. Thus, your way will be a polygonal chain from (0,0) to (n,n), comprising of all things considered n line portions where each section has positive integer length and vertical and level fragments substitute. Not all ways are equivalent. You have n integers c1,c2,… ,cn where ci is the expense of the I-th section. Utilizing these costs we can characterize the expense of the way as the amount of lengths of the portions of this way duplicated by their expense, I. e. on the off chance that the way comprises of k sections (k≤n), the expense of the way is equivalent to ∑i=1kci⋅lengthi (fragments are numbered from 1 to k in the request they are in the way). Find the way of the base expense and print its expense. Input The principal line contains the single integer t (1≤t≤1000) — the number of experiments. The…
Simplify n∧(¬q∨q) to n
Use the substitution method to identify the big-Oh of the represented by the following recurrence relation. Note: c is a constant. T(n) = cn + T(n/2) + T(n/2), T(1) = c
Let ap = 1, an = an-1 + 3 be the recurrence relation of algorithm A and T(1) = 1, T(n) = T(n/5)+n be the recurrence relation of algorithm B. 1. Find the solution for both relations. Use any method.
In order to minimize an FA, you have to try and determine if any of the states are actually the same state. You can do this by a table a table and finally by tables that shaped table All the results are stored in a nifty "stair step" that prevents any state from being compared to
The set of letters S consists of 30 As, 6 Bs, 24 Cs, 15 Ds, and 15 Es. The set of letters T consists of 25 As, 20 Bs, 15 Cs, 5 Ds and 35 Es. What is the mutual index of coincidence between sets S and T? Leave your answer as a fraction in lowest terms

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