Consider the following circuit R Us +v₁ (t)- vilt) + 3L Vo(t) For this circuit, the input voltage is vs (t) = 0.1 cos(450t +30°) V. Assume R = 100 2 and L = 50mH. By analyzing the circuit using the concept of phasors and basic circuit laws in the frequency domain i.e. w domain, fill in the following blanks. Use j to denote a complex term. 2. The phasor notation for v, (t) is V₂ (w) = 0.1-30 V. Use the "<" ("less than" or "<" key on your board) to denote the angle. Example: for an angle of 90°, you would type <90 as your answer without the degree symbol. b. The resistance is ZR = 100 Ω c. The inductive impedance is Z = j22.5 Ω d. Using voltage division in the frequency domain, the phasor form of the current in the circuit is I (w) = 0.0009-17.319 A. Enter the amplitude up to 4 decimal places e. The sinusoidal form of the inductor voltage i (t) = 0.0009cos(450t+17 A. Enter the amplitude up to 4 decimal places. Ignore the degree symbol when entering your

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c, d, and e please

### Analyzing an RL Circuit in the Frequency Domain

Consider the following RL circuit:

![Circuit Diagram](image-link) 
*Note: The link above is a placeholder for the circuit diagram which includes a resistor \( R \) and an inductor \( L \) in series with a voltage source \( V_s \). The voltages across the resistor and inductor are denoted as \( v_1(t) \) and \( v_0(t) \), respectively.*

For this circuit, the input voltage is \( v_s(t) = 0.1 \cos(450t + 30^\circ) \) V. Assume \( R = 100 \, \Omega \) and \( L = 50 \, \text{mH} \).

By analyzing the circuit using the concept of phasors and basic circuit laws in the frequency domain (i.e., \(\omega\) domain), fill in the following blanks. Use \( j \) to denote a complex term.

a. The phasor notation for \( v_s(t) \) is \( V_s(\omega) \).
   \[
   V_s(\omega) = 0.1 < 30 \text{ V}
   \]
   Use the "<" ("less than" key on your board) to denote the angle.

b. The resistance is \( Z_R \).
   \[
   Z_R = 100 \, \Omega
   \]

c. The inductive impedance is \( Z_L \).
   \[
   Z_L = j22.5 \, \Omega
   \]

d. Using voltage division in the frequency domain, the phasor form of the current in the circuit is \( I(\omega) \).
   \[
   I(\omega) = 0.0009 < 17.319 \text{ A}
   \]
   Enter the amplitude up to 4 decimal places.

e. The sinusoidal form of the inductor voltage \( i(t) \).
   \[
   i(t) = 0.0009 \cos(450t + 17^\circ) \text{ A}
   \]
   Enter the amplitude up to 4 decimal places. Ignore the degree symbol when entering your answer.
Transcribed Image Text:### Analyzing an RL Circuit in the Frequency Domain Consider the following RL circuit: ![Circuit Diagram](image-link) *Note: The link above is a placeholder for the circuit diagram which includes a resistor \( R \) and an inductor \( L \) in series with a voltage source \( V_s \). The voltages across the resistor and inductor are denoted as \( v_1(t) \) and \( v_0(t) \), respectively.* For this circuit, the input voltage is \( v_s(t) = 0.1 \cos(450t + 30^\circ) \) V. Assume \( R = 100 \, \Omega \) and \( L = 50 \, \text{mH} \). By analyzing the circuit using the concept of phasors and basic circuit laws in the frequency domain (i.e., \(\omega\) domain), fill in the following blanks. Use \( j \) to denote a complex term. a. The phasor notation for \( v_s(t) \) is \( V_s(\omega) \). \[ V_s(\omega) = 0.1 < 30 \text{ V} \] Use the "<" ("less than" key on your board) to denote the angle. b. The resistance is \( Z_R \). \[ Z_R = 100 \, \Omega \] c. The inductive impedance is \( Z_L \). \[ Z_L = j22.5 \, \Omega \] d. Using voltage division in the frequency domain, the phasor form of the current in the circuit is \( I(\omega) \). \[ I(\omega) = 0.0009 < 17.319 \text{ A} \] Enter the amplitude up to 4 decimal places. e. The sinusoidal form of the inductor voltage \( i(t) \). \[ i(t) = 0.0009 \cos(450t + 17^\circ) \text{ A} \] Enter the amplitude up to 4 decimal places. Ignore the degree symbol when entering your answer.
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