Consider the following candidate PRG: defined by the following rule: G: {0, 1}"→ {0, 1}"+¹ G(1₁ In) = InIn-1 I1In Show that G is not a PRG. Consider the following candidate PRG: G: {0, 1}"{0, 1}"+¹ defined as follows: First G(r₁ rn) computes f = Σ (that is, is the number of one's in the given input string). Next, it computes y = 2112@n. Finally, it outputs the n+1 bit-string: 12 YIt+1 n That is, it places y in the 'th index where f is based on the input string. Show that this is not a PRG.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Consider the following candidate PRG:
defined by the following rule:
G: {0, 1)" {0, 1}"+¹
G(1₁ In) = InIn-11n,
Show that G is not a PRG.
Consider the following candidate PRG:
G: {0,1}" - >
defined as follows: First G(rr) computes =
(that is, is the number of one's in the
given input string). Next, it computes y = 112n. Finally, it outputs the n+1 bit-string:
{0,1}"+¹
12 1ye+1 n
That is, it places y in the 'th index where is based on the input string. Show that this is not a PRG.
Transcribed Image Text:Consider the following candidate PRG: defined by the following rule: G: {0, 1)" {0, 1}"+¹ G(1₁ In) = InIn-11n, Show that G is not a PRG. Consider the following candidate PRG: G: {0,1}" - > defined as follows: First G(rr) computes = (that is, is the number of one's in the given input string). Next, it computes y = 112n. Finally, it outputs the n+1 bit-string: {0,1}"+¹ 12 1ye+1 n That is, it places y in the 'th index where is based on the input string. Show that this is not a PRG.
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